Python - 用逗号分割，跳过括号内的内容

Question

我需要用逗号分割字符串，但我对这种情况有一个问题：

TEXT EXAMPLE (THIS IS (A EXAMPLE, BUT NOT WORKS, FOR ME)), SECOND , THIRD

我想拆分并得到：

var[0] = "TEXT EXAMPLE (THIS IS (A EXAMPLE, BUT NOT WORKS, FOR ME))"
var[1] = "SECOND"
var[2] = "THIRD"

谢谢

Answer 1

您可以使用这个基于负向前瞻的正则表达式：

,(?!(?:[^(]*\([^)]*\))*[^()]*\))

该正则表达式正在查找带有断言的逗号，以确保逗号不在括号中。这是通过使用负前瞻来完成的，该前瞻首先消耗所有匹配(，)然后消耗). 这假设括号是平衡的且未转义。

正则表达式演示

代码：

>>> s = 'TEXT EXAMPLE (THIS IS (A EXAMPLE, BUT NOT WORKS, FOR ME)), SECOND , THIRD'
print re.split(r',(?!(?:[^(]*\([^)]*\))*[^()]*\))', s)

['TEXT EXAMPLE (THIS IS (A EXAMPLE, BUT NOT WORKS, FOR ME))', ' SECOND ', ' THIRD']

或者：

>>> s = 'TEXT EXAMPLE (THIS, IS (A EXAMPLE, BUT NOT WORKS, FOR ME)), SECOND , THIRD'
>>> print re.split(r',(?!(?:[^(]*\([^)]*\))*[^()]*\))', s)
['TEXT EXAMPLE (THIS, IS (A EXAMPLE, BUT NOT WORKS, FOR ME))', ' SECOND ', ' THIRD']