Aun*_*ung 3 counter dictionary julia
我a1和a2朱莉娅有两本词典.
a1 = {"A"=>1, "B"=>2}
a2 = {"A"=>4, "B"=>1, "C"=>3}
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我想把它结合起来得到这个.
final={"A"=>5, "B"=>3, "C"=>3}
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在Python中,我将字典转换为集合计数器并将它们组合在一起.
看看DataStructures.jl计数器.
julia> using DataStructures: counter
julia> a1 = Dict{ASCIIString, Int64}("A"=>1, "B"=>2)
Dict{ASCIIString,Int64} with 2 entries:
"B" => 2
"A" => 1
julia> a2 = Dict{ASCIIString, Int64}("A"=>4, "B"=>1, "C"=>3)
Dict{ASCIIString,Int64} with 3 entries:
"B" => 1
"A" => 4
"C" => 3
julia> merge(counter(a1), counter(a2)).map
Dict{ASCIIString,Int64} with 3 entries:
"B" => 3
"A" => 5
"C" => 3
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小智 5
对于现在查看此内容的任何人,counter不再需要 - 使用merge(+, a1, a2).
julia> a1 = Dict("A"=>1, "B"=>2)
Dict{String,Int64} with 2 entries:
"B" => 2
"A" => 1
julia> a2 = Dict("A"=>4, "B"=>1, "C"=>3)
Dict{String,Int64} with 3 entries:
"B" => 1
"A" => 4
"C" => 3
julia> merge(+, a1, a2)
Dict{String,Int64} with 3 entries:
"B" => 3
"A" => 5
"C" => 3
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