撤销权限android.permission.CALL_PHONE

Question

我正在尝试以编程方式使用以下代码调用数字:

 String number = ("tel:" + numTxt.getText());
 Intent intent = new Intent(Intent.ACTION_CALL);
 intent.setData(Uri.parse(number));
 startActivity(intent);

我在Manifest中设置了权限:

<uses-permission android:name="android.permission.CALL_PHONE"/>

我正在使用真实设备进行测试和调试,它是带有Android M的Nexus 5,我的compileSdkVersion是23.我得到以下安全例外:

error: Permission Denial: starting Intent { act=android.intent.action.CALL dat=tel:xxxxxxxxxx cmp=com.android.server.telecom/.components.UserCallActivity } from ProcessRecord{cbbd7c1 5228:com.dialerTest.DialerApp/u0a96} (pid=5228, uid=10096) with revoked permission android.permission.CALL_PHONE

我在网络和这个社区搜索了类似的问答,但找不到答案.任何帮助将不胜感激.

Answer 1

在android 6.0(Api lvl 23)中,我们有一些名为"运行时权限"的东西.你必须阅读它.

你可以在这里找到文档.

Answer 2

权限CALL_PHONE属于危险权限组.
因此,如果您的应用目标SDK为23或更高且您的设备在Android 6.0或更高版本上运行,则必须在应用运行时请求CALL_PHONE权限.

示例:

String number = ("tel:" + numTxt.getText());
mIntent = new Intent(Intent.ACTION_CALL);
mIntent.setData(Uri.parse(number));
// Here, thisActivity is the current activity
if (ContextCompat.checkSelfPermission(thisActivity,
            Manifest.permission.CALL_PHONE)
    != PackageManager.PERMISSION_GRANTED) {

    ActivityCompat.requestPermissions(thisActivity,
            new String[]{Manifest.permission.CALL_PHONE},
            MY_PERMISSIONS_REQUEST_CALL_PHONE);

    // MY_PERMISSIONS_REQUEST_CALL_PHONE is an
    // app-defined int constant. The callback method gets the
    // result of the request.
} else {
    //You already have permission
     try {
        startActivity(mIntent); 
    } catch(SecurityException e) {
       e.printStackTrace();
   }
}

当您的应用请求权限时,系统会向用户显示一个对话框.当用户响应时,系统会调用您应用的onRequestPermissionsResult()方法,并向其传递用户响应.

@Override
public void onRequestPermissionsResult(int requestCode,
    String permissions[], int[] grantResults) {
  switch (requestCode) {
    case MY_PERMISSIONS_REQUEST_CALL_PHONE: {
        // If request is cancelled, the result arrays are empty.
        if (grantResults.length > 0
            && grantResults[0] == PackageManager.PERMISSION_GRANTED) {

            // permission was granted, yay! Do the phone call

        } else {

            // permission denied, boo! Disable the
            // functionality that depends on this permission.
        }
        return;
    }

    // other 'case' lines to check for other
    // permissions this app might request
  }
}

Answer 3

你的代码只有在你创建一个时才能工作ACTION_DIAL，而不是ACTION_CALL在你需要请求许可的地方，所以如果你想打电话，请按照这个例子：

清单：

<uses-permission android:name="android.permission.CALL_PHONE" />

代码：

import static android.Manifest.permission.CALL_PHONE;

Intent i = new Intent(Intent.ACTION_CALL);
i.setData(Uri.parse("tel:0612312312"));
/*
Intent i = new Intent(Intent.ACTION_DIAL);
i.setData(Uri.parse("tel:0612312312"));
if (i.resolveActivity(getPackageManager()) != null) {
      startActivity(i);
}*/
if (ContextCompat.checkSelfPermission(getApplicationContext(), CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {
      startActivity(i);
} else {
      requestPermissions(new String[]{CALL_PHONE}, 1);
}