在浏览器中点击app时播放框架挂起

Question

我在Play中运行一个应用程序activator run,也许是5次中的3次,它会挂起,当我去的时候http://localhost:9000/,它只是坐在那里永远旋转.

我也看到了很多promise timed out错误.

我应该在哪里寻找这个问题？

我开始记录logLevel := Level.Debug,但我没有看到任何错误.当应用程序正在旋转时,我看不到任何日志记录.

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如果我让它坐下并旋转很长时间(约5分钟),它最终会出现这个错误:

[info] play.api.http.HttpErrorHandlerExceptions$$anon$1: Execution exception[[PrivilegedActionException: null]]
[info]  at play.api.http.HttpErrorHandlerExceptions$.throwableToUsefulException(HttpErrorHandler.scala:265) ~[play_2.11-2.4.3.jar:2.4.3]
[info]  at play.api.http.DefaultHttpErrorHandler.onServerError(HttpErrorHandler.scala:191) ~[play_2.11-2.4.3.jar:2.4.3]
[info]  at play.core.server.Server$class.logExceptionAndGetResult$1(Server.scala:50) [play-server_2.11-2.4.3.jar:2.4.3]
[info]  at play.core.server.Server$$anonfun$getHandlerFor$4.apply(Server.scala:59) [play-server_2.11-2.4.3.jar:2.4.3]
[info]  at play.core.server.Server$$anonfun$getHandlerFor$4.apply(Server.scala:57) [play-server_2.11-2.4.3.jar:2.4.3]
[info]  at scala.util.Either$RightProjection.flatMap(Either.scala:522) [scala-library.jar:na]
[info]  at play.core.server.Server$class.getHandlerFor(Server.scala:57) [play-server_2.11-2.4.3.jar:2.4.3]
[info]  at play.core.server.NettyServer.getHandlerFor(NettyServer.scala:33) [play-netty-server_2.11-2.4.3.jar:2.4.3]
[info]  at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$8.apply(PlayDefaultUpstreamHandler.scala:139) [play-netty-server_2.11-2.4.3.jar:2.4.3]
[info]  at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$8.apply(PlayDefaultUpstreamHandler.scala:139) [play-netty-server_2.11-2.4.3.jar:2.4.3]
[info] Caused by: java.security.PrivilegedActionException: null
[info]  at java.security.AccessController.doPrivileged(Native Method) ~[na:1.8.0_20]
[info]  at play.runsupport.Reloader$.play$runsupport$Reloader$$withReloaderContextClassLoader(Reloader.scala:39) ~[na:na]
[info]  at play.runsupport.Reloader.reload(Reloader.scala:321) ~[na:na]
[info]  at play.core.server.DevServerStart$$anonfun$mainDev$1$$anon$1$$anonfun$get$1.apply(DevServerStart.scala:113) ~[play-server_2.11-2.4.3.jar:2.4.3]
[info]  at play.core.server.DevServerStart$$anonfun$mainDev$1$$anon$1$$anonfun$get$1.apply(DevServerStart.scala:111) ~[play-server_2.11-2.4.3.jar:2.4.3]
[info]  at scala.concurrent.impl.Future$PromiseCompletingRunnable.liftedTree1$1(Future.scala:24) ~[scala-library.jar:na]
[info]  at scala.concurrent.impl.Future$PromiseCompletingRunnable.run(Future.scala:24) ~[scala-library.jar:na]
[info]  at java.util.concurrent.ForkJoinTask$RunnableExecuteAction.exec(ForkJoinTask.java:1423) ~[na:1.8.0_20]
[info]  at java.util.concurrent.ForkJoinTask.doExec(ForkJoinTask.java:289) ~[na:1.8.0_20]
[info]  at java.util.concurrent.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:902) ~[na:1.8.0_20]
[info] Caused by: java.util.concurrent.TimeoutException: Futures timed out after [300000 milliseconds]
[info]  at scala.concurrent.impl.Promise$DefaultPromise.ready(Promise.scala:219) ~[scala-library.jar:na]
[info]  at scala.concurrent.impl.Promise$DefaultPromise.result(Promise.scala:223) ~[scala-library.jar:na]
[info]  at scala.concurrent.Await$$anonfun$result$1.apply(package.scala:190) ~[scala-library.jar:na]
[info]  at scala.concurrent.BlockContext$DefaultBlockContext$.blockOn(BlockContext.scala:53) ~[scala-library.jar:na]
[info]  at scala.concurrent.Await$.result(package.scala:190) ~[scala-library.jar:na]
[info]  at play.forkrun.ForkRun$$anonfun$askForReload$1.apply(ForkRun.scala:127) ~[na:na]
[info]  at play.forkrun.ForkRun$$anonfun$askForReload$1.apply(ForkRun.scala:125) ~[na:na]
[info]  at play.runsupport.Reloader$$anonfun$reload$1.apply(Reloader.scala:323) ~[na:na]
[info]  at play.runsupport.Reloader$$anon$3.run(Reloader.scala:43) ~[na:na]
[info]  at java.security.AccessController.doPrivileged(Native Method) ~[na:1.8.0_20]

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我应该提一下,这是一个非常简单的应用程序.到目前为止,它只是渲染一些HTML.

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它太糟糕了,因为它似乎在框架中有很多好处,但它只是缓慢且非常不可靠.

Answer 1

fork in run := true从 Activators UI（用于生成进程）启动应用程序时始终添加，因此请停止使用给定应用程序的 UI（可能在 IDE 中添加启动配置）或始终记住清除/注释/设置为 false。