dav*_*mah 6 java arrays sorting heap heapsort
我试图在java中编写一个heapsort方法,但它并不像我想要的那样工作:
public class HeapSort {
private static int n;
private static void swap(int[] A, int a, int b)
{
int tmp = A[a];
A[a] = A[b];
A[b] = tmp;
}
private static void insert(int[] A, int i)
{
int left = i * 2;
int right = left + 1;
int max = i;
if (left <= n && A[left] < A[max]){
max = left;
}
if (right <= n && A[right] > A[max]) {
max = right;
}
if (max != i) {
swap(A, i, max);
insert(A, max);
}
}
public static void HeapSort(int[] A)
{
n = A.length - 1;
for (int i = n / 2; i >= 0; i--)
insert(A, i);
for (int i = n; i > 0; i--) {
swap(A, 0, i);
n--;
insert(A, 0);
}
}
public static void main(String[] args){
int[] A = new int[] {9, 2, 8, 1, 4};
System.out.println(java.util.Arrays.toString(arr));
HeapSort(A);
System.out.println(java.util.Arrays.toString(arr));
}
}
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它适用于某些数组,但是像9,2,8,1,4这样的数组将被分类为1,4,2,8,9.那么为什么不以正确的方式对数组进行排序呢?
if (left <= n && A[left] > A[i]){
max = left;
}
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试试这个看看。我已经制作了完整的程序如下。这对于您提供的输入效果很好。
public class HeapSort {
private static int n;
private static void swap(int[] A, int a, int b)
{
int tmp = A[a];
A[a] = A[b];
A[b] = tmp;
}
private static void insert(int[] A, int i)
{
int left = i * 2;
int right = left + 1;
int max = i;
if (left <= n && A[left] > A[i]){
max = left;
}
if (right <= n && A[right] > A[max]) {
max = right;
}
if (max != i) {
swap(A, i, max);
insert(A, max);
}
}
public static void HeapSort(int[] A)
{
n = A.length - 1;
for (int i = n / 2; i >= 0; i--)
insert(A, i);
for (int i = n; i > 0; i--) {
swap(A, 0, i);
n--;
insert(A, 0);
}
}
public static void main(String[] args){
int[] A = new int[] {19, 6, 28, 1, 0};
int[] B = new int[] {1, 2, 4, 8, 9, 0};
System.out.println(java.util.Arrays.toString(A));
System.out.println(java.util.Arrays.toString(B));
HeapSort(A);
HeapSort(B);
System.out.println(java.util.Arrays.toString(A));
System.out.println(java.util.Arrays.toString(B));
}
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}
这是输出。
[19, 6, 28, 1, 0]
[1, 2, 4, 8, 9, 0]
[0, 1, 6, 19, 28]
[0, 1, 2, 4, 8, 9]
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