MySQL查询:
$sSix = "SELECT count(*) as count FROM `timers` WHERE `real_id` = {$row['real_id']}";
$rSix = mysql_query($sSix, $conn2);
echo mysql_error(); die;
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结果:'where子句'中的未知列'985_1445542200'
列名是real_id结果显示列'985_1445542200'.
你能告诉我可能的错误原因吗?
你需要报价WHERE.像这样:
$sSix = "SELECT count(*) as count FROM `timers` WHERE `real_id` = '{$row['real_id']}'";
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此外,请考虑使用较新的mysqli_功能,或者PDO因为旧mysql_功能将来会停止工作.