如何在C++中捕获char*异常

Question

我试图在main()中捕获char*类型异常,但程序崩溃时出现以下消息:在抛出'char const*'实例后调用terminate这是代码:

#include <iostream>

int main ()
{
    char myarray[10];
    try
    {
        for (int n=0; n<=10; n++)
        {
            if (n>9)
            throw "Out of range";
            myarray[n]='a';
        }
    }
    catch (char * str)
    {
        std::cout << "Exception: " << str << std::endl;
    }
    return 0;
}

Answer 1

使用const:

catch (const char * str)
    {
        std::cout << "Exception: " << str << std::endl;
    }