基本上我试图通过unlisting
和paste
-ing一个列表来派生SELECT语句的WHERE部分,其中列表名称代表数据库TABLE列和相应的列表值等于WHERE子句的参数.这是一个简化的例子......
lst <- list(DATE=as.Date('2015-10-25'), NUM="0001", PROD="SOMETHING")
lst
$DATE
[1] "2015-10-25"
$NUM
[1] "0001"
$PROD
[1] "SOMETHING"
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理想情况下,这将被转换为(从第二行开始的有趣位WHERE
):
"SELECT SOME_COLUMNS WHERE
DATE = '", lst$DATE, "' AND
NUM = '", lst$NUM, "' AND
PROD = '" lst$PROD ,"'")
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我很确定有人知道一些奇特的组合apply()
,
paste(..,collapse ="' AND ")
和/或substitute()
那可以以优雅的形式实现,但我被卡住了.
我不知道这是否足够优雅,但应该有效:
sql <- paste0("SELECT ",
paste0(names(lst),collapse=','),
" WHERE\n",
paste(lapply(names(lst),function(x)paste0(x," = '",lst[[x]],"'")),collapse="AND\n"))
> cat(sql)
SELECT DATE,NUM,PROD WHERE
DATE = '2015-10-25'AND
NUM = '0001'AND
PROD = 'SOMETHING'
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