Python - sns.color_palette输出为Bokeh的十六进制数

Question

什么是输出格式

sns.color_palette('Reds', 5)?

如何将其转换为十六进制数？

运行上面的命令可以得到以下输出:

[(0.99358708227381987, 0.83234141714432663, 0.76249136363758763), (0.98823529481887817, 0.62614381313323975, 0.50849674145380652), (0.98357554884517895, 0.4127950837799147, 0.28835064675293715), (0.89019608497619629, 0.18562091638644537, 0.15294117977221808), (0.69439448188332953, 0.070034602810354785, 0.092318341048324815)] 

如何将其转换为如下输出:

["#9b59b6", "#3498db", "#95a5a6", "#e74c3c", "#34495e", "#2ecc71", "#43A16F"]

Answer 1

更好(假设seaborn> = 0.6):

import seaborn as sns
pal = sns.color_palette('Reds', 5)
pal.as_hex()

['#fdd4c2', '#fca082', '#fb694a', '#e32f27', '#b11218']