联系人缺少ios中的一些必需的密钥描述符

Question

我使用以下方法检索所有联系人

- (void)getAllContacts:(void(^)(NSArray *array))handler
{
    CNAuthorizationStatus status = [CNContactStore authorizationStatusForEntityType:CNEntityTypeContacts];

    if (status == CNAuthorizationStatusDenied || status == CNAuthorizationStatusDenied)
    {
        UIAlertController *alert = [UIAlertController alertControllerWithTitle:nil message:@"This app previously was refused permissions to contacts; Please go to settings and grant permission to this app so it can use contacts" preferredStyle:UIAlertControllerStyleAlert];
        [alert addAction:[UIAlertAction actionWithTitle:@"OK" style:UIAlertActionStyleDefault handler:nil]];
        [self presentViewController:alert animated:TRUE completion:nil];
        return;
    }

    CNContactStore *store = [[CNContactStore alloc] init];
    [store requestAccessForEntityType:CNEntityTypeContacts completionHandler:^(BOOL granted, NSError * _Nullable error) {

        // make sure the user granted us access
        if (!granted)
        {
            dispatch_async(dispatch_get_main_queue(), ^{
                // user didn't grant access;
                // so, again, tell user here why app needs permissions in order  to do it's job;
                // this is dispatched to the main queue because this request could be running on background thread
            });
            return;
        }

        // build array of contacts
        NSMutableArray *contacts = [NSMutableArray array];

        NSError *fetchError;
        CNContactFetchRequest *request = [[CNContactFetchRequest alloc] initWithKeysToFetch:@[CNContactIdentifierKey, CNContactEmailAddressesKey, CNContactBirthdayKey, CNContactImageDataKey, CNContactPhoneNumbersKey, [CNContactFormatter descriptorForRequiredKeysForStyle:CNContactFormatterStyleFullName]]];

        BOOL success = [store enumerateContactsWithFetchRequest:request error:&fetchError usingBlock:^(CNContact *contact, BOOL *stop) {

            [contacts addObject:contact];
        }];

        if (!success)
        {
            NSLog(@"error = %@", fetchError);
            return;
        }
        handler((NSArray *)contacts);
   }];

}

表格中列出了联系人.现在我试图从``中选择特定的联系方式,

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
    CNContact *contact = [arrContacts objectAtIndex:indexPath.row];
    NSArray *keys = @[CNContactIdentifierKey, CNContactEmailAddressesKey, CNContactBirthdayKey, CNContactImageDataKey, CNContactPhoneNumbersKey, [CNContactFormatter descriptorForRequiredKeysForStyle:CNContactFormatterStyleFullName]];
    CNContactViewController *contactController = [CNContactViewController viewControllerForContact:contact];
    contactController.delegate = self;
    contactController.allowsEditing = YES;
    contactController.allowsActions = YES;
    contactController.displayedPropertyKeys = keys;
    [self.navigationController pushViewController:contactController animated:TRUE];
}

但它说

联系人0x7fc732654530缺少一些必需的密钥描述符

如果有人知道,请帮我解决.谢谢.

Answer 1

在keysToFetch数组的末尾添加"CNContactViewController.descriptorForRequiredKeys".

在我这样做之后为我工作.

例:

NSArray *keysToFetch = @[CNContactIdentifierKey, CNContactGivenNameKey, CNContactFamilyNameKey, CNContactPhoneNumbersKey, CNContactImageDataAvailableKey, CNContactImageDataKey, CNContactViewController.descriptorForRequiredKeys];