定制转换器与Moshi子类

Question

我有一个User类.还有两个子类.父母和孩子.我使用{"user":"..."}从我的服务器获取json,需要根据user.type将其转换为父级或子级.

据我所知,我需要以这种方式添加自定义转换器:

        Moshi moshi = new Moshi.Builder()
            .add(new UserAdapter())
            .build();

这是我对UserAdapter的实现.我知道它是假的,但它甚至不能这样工作:

public class UserAdapter {

@FromJson
User fromJson(String userJson) {
    Moshi moshi = new Moshi.Builder().build();
    try {
        JSONObject jsonObject = new JSONObject(userJson);
        String accountType = jsonObject.getString("type");

        switch (accountType) {
            case "Child":
                JsonAdapter<Child> childJsonAdapter = moshi.adapter(Child.class);
                return childJsonAdapter.fromJson(userJson);
            case "Parent":
                JsonAdapter<Parent> parentJsonAdapter = moshi.adapter(Parent.class);
                return parentJsonAdapter.fromJson(userJson);

        }
    } catch (JSONException | IOException e) {
        e.printStackTrace();
    }

    return null;
}

@ToJson
String toJson(User user) {
    Moshi moshi = new Moshi.Builder().build();
    JsonAdapter<User> jsonAdapter = moshi.adapter(User.class);
    String toJson = jsonAdapter.toJson(user);
    return toJson;
}

首先,我使用此代码获得以下异常.

com.squareup.moshi.JsonDataException: Expected a string but was BEGIN_OBJECT at path $.user

第二,我相信有更好的方法.请指教.

UPD.这是错误的堆栈跟踪:

 com.squareup.moshi.JsonDataException: Expected a name but was BEGIN_OBJECT at path $.user
 at com.squareup.moshi.JsonReader.nextName(JsonReader.java:782)
 at com.squareup.moshi.ClassJsonAdapter.fromJson(ClassJsonAdapter.java:141)
 at com.squareup.moshi.JsonAdapter$1.fromJson(JsonAdapter.java:68)
 at com.squareup.moshi.JsonAdapter.fromJson(JsonAdapter.java:33)
 at retrofit.MoshiResponseBodyConverter.convert(MoshiResponseBodyConverter.java:33)
 at retrofit.MoshiResponseBodyConverter.convert(MoshiResponseBodyConverter.java:23)
 at retrofit.OkHttpCall.parseResponse(OkHttpCall.java:148)
 at retrofit.OkHttpCall.execute(OkHttpCall.java:116)
 at retrofit.RxJavaCallAdapterFactory$CallOnSubscribe.call(RxJavaCallAdapterFactory.java:111)
 at retrofit.RxJavaCallAdapterFactory$CallOnSubscribe.call(RxJavaCallAdapterFactory.java:88)
 at rx.Observable$2.call(Observable.java:162)
 at rx.Observable$2.call(Observable.java:154)
 at rx.Observable$2.call(Observable.java:162)
 at rx.Observable$2.call(Observable.java:154)
 at rx.Observable.unsafeSubscribe(Observable.java:7710)
 at rx.internal.operators.OperatorSubscribeOn$1$1.call(OperatorSubscribeOn.java:62)
 at rx.internal.schedulers.ScheduledAction.run(ScheduledAction.java:55)
 at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:422)
 at java.util.concurrent.FutureTask.run(FutureTask.java:237)
 at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.access$201(ScheduledThreadPoolExecutor.java:152)
 at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:265)
 at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1112)
 at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:587)
 at java.lang.Thread.run(Thread.java:818)

Answer 1

在我看来,这就像您要为自定义de /序列化JSON数据所遵循的示例:https://github.com/square/moshi#another-example

它使用对应于JSON结构的中间类,并且Moshi将自动为您充气.然后,您可以使用膨胀的数据来构建专门的用户类.例如:

// Intermediate class with JSON structure
class UserJson {
  // Common JSON fields
  public String type;
  public String name;
  // Parent JSON fields
  public String occupation;
  public Long salary;
  // Child JSON fields
  public String favorite_toy;
  public Integer grade;
}

abstract class User {
  public String type;
  public String name;
}

final class Parent extends User {
  public String occupation;
  public Long salary;
}

final class Child extends User {
  public String favoriteToy;
  public Integer grade;
}

现在,适配器:

class UserAdapter {
  // Note that you pass in a `UserJson` object here
  @FromJson User fromJson(UserJson userJson) {
    switch (userJson.type) {
    case "Parent":
      final Parent parent = new Parent();
      parent.type = userJson.type;
      parent.name = userJson.name;
      parent.occupation = userJson.occupation;
      parent.salary = userJson.salary;
      return parent;
    case "Child":
      final Child child = new Child();
      child.type = userJson.type;
      child.name = userJson.name;
      child.favoriteToy = userJson.favorite_toy;
      child.grade = userJson.grade;
      return child;
    default:
      return null;
    }
  }

  // Note that you return a `UserJson` object here.
  @ToJson UserJson toJson(User user) {
    final UserJson json = new UserJson();
    if (user instanceof Parent) {
      json.type = "Parent";
      json.occupation = ((Parent) user).occupation;
      json.salary = ((Parent) user).salary;
    } else {
      json.type = "Child";
      json.favorite_toy = ((Child) user).favoriteToy;
      json.grade = ((Child) user).grade;
    }
    json.name = user.name;
    return json;
  }
}

我认为这更清晰,并允许Moshi做它的事情,即从JSON创建对象并从对象创建JSON.没有老式的杂乱无章JSONObject!

去测试:

Child child = new Child();
child.type = "Child";
child.name = "Foo";
child.favoriteToy = "java";
child.grade = 2;
Moshi moshi = new Moshi.Builder().add(new UserAdapter()).build();
try {
  // Serialize
  JsonAdapter<User> adapter = moshi.adapter(User.class);
  String json = adapter.toJson(child);
  System.out.println(json);
  // Output is: {"favorite_toy":"java","grade":2,"name":"Foo","type":"Child"}

  // Deserialize
  // Note the cast to `Child`, since this adapter returns `User` otherwise.
  Child child2 = (Child) adapter.fromJson(json);
  System.out.println(child2.name);
  // Output is: Foo
} catch (IOException e) {
  e.printStackTrace();
}

Answer 2

现在有一种更好的方法可以做到这一点，即使用PolymorphicJsonAdapterFactory. 请参阅https://proandroiddev.com/moshi-polymorphic-adapter-is-d25deebbd7c5