Ari*_*jee 3 c# asp.net-mvc identity asp.net-mvc-5 asp.net-identity
我正在使用基本的mvc-5登录方法,只是尝试在成功时访问用户ID
[HttpPost]
[AllowAnonymous]
[ValidateAntiForgeryToken]
public async Task<ActionResult> Login(LoginViewModel model, string returnUrl)
{
if (!ModelState.IsValid)
{
return View(model);
}
// This doesn't count login failures towards account lockout
// To enable password failures to trigger account lockout, change to shouldLockout: true
var result = await SignInManager.PasswordSignInAsync(model.Email, model.Password, model.RememberMe, shouldLockout: false);
switch (result)
{
case SignInStatus.Success:
string userId = User.Identity.GetUserId();
returnUrl = CheckUserRoleAndRedirect();
return RedirectToLocal(returnUrl);
case SignInStatus.LockedOut:
return View("Lockout");
case SignInStatus.RequiresVerification:
return RedirectToAction("SendCode", new { ReturnUrl = returnUrl, RememberMe = model.RememberMe });
case SignInStatus.Failure:
default:
ModelState.AddModelError("", "Invalid login attempt.");
return View(model);
}
}
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这里string userId = User.Identity.GetUserId();userId第一次返回null,但下次它正常工作
登录后(并重定向到另一个页面),IPrincipal.IIdentity应该是a ClaimsIdentity.你可以试试这个:
var claimsIdentity = User.Identity as ClaimsIdentity;
if (claimsIdentity != null)
{
// the principal identity is a claims identity.
// now we need to find the NameIdentifier claim
var userIdClaim = claimsIdentity.Claims
.FirstOrDefault(x => x.Type == ClaimTypes.NameIdentifier);
if (userIdClaim != null)
{
var userIdValue = userIdClaim.Value;
}
}
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这应该适合你.如果仍然无法获取id,则必须在服务器将身份验证cookie写入浏览器之前重定向到另一个页面.
或者另一种方法是:
switch (result)
{
case SignInStatus.Success:
ApplicationUser user = UserManager.FindByName(model.UserName);
string UserId = user.Id;
returnUrl = CheckUserRoleAndRedirect();
return RedirectToLocal(returnUrl);
}
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一旦调用,SignInAsync就会创建一个AuthenticationResponseGrant,并且在下次调用之前,User.Identity中不会提供详细信息.
但是,您可以通过直接访问AuthenticationResponseGrant.Identity来解决此问题:
var Grant = SignInManager.AuthenticationManager.AuthenticationResponseGrant;
string UserId = Grant.Identity.GetUserId();
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当然,没有必要映射,Grant但它使代码更具可读性.
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