如何检查任何true实例的布尔数组,然后从相应的数组中打印这些实例？

Question

我有两个数组,需要[]并购买[].need []是一个String数组,包含根据boolean buying []数组的相应索引值被视为buy(true)或need(false)的7个不同项.我想打印购买的物品清单只有当项目实际上已经买了.但是,我目前的技术是在需要时产生无限循环的项目[1].

public static void listSupplies(String[] need, boolean[] bought){
        /*Line of code in the while loop checks the whole array for an instance of 'true'*/
        if(areAllFalse(bought) == true){
            System.out.println("Inventory:");
            for (int i = 0; i < need.length; i++) { 
                if(bought[i] == true){
                    System.out.print(need[i] + " "); System.out.println(" "); break;
                }
            }
            System.out.println("");
        }
        System.out.println("Need:");
        for (int i = 0; i < need.length; i++) { 
            while(bought[i] == false){
                System.out.print(need[i] + " "); System.out.println(" ");
            }
        }
        System.out.println("");
        mainMenu();
    }
    //Checks to see if the array contains 'true'
    public static boolean areAllFalse(boolean[] array){
        for(boolean val : array){
            if(val) 
                return true;
        } 
        return false;
    }

(在此代码之前,数组被声明为:)

String[] needInit = {"Broom", "School robes", "Wand", "The Standard Book of Spells", "A History of Magic", "Magical Drafts and Potions", "Cauldron"};
boolean bought[] = new boolean[7];

Answer 1

你的while循环导致无限循环.你不需要它.如果您只想打印购买的商品:

变化:

    for (int i = 0; i < need.length; i++) { 
        while(bought[i] == false){ // here's the cause of the infinite loop
            System.out.print(need[i] + " "); System.out.println(" ");
        }
    }

至 :

    for (int i = 0; i < need.length; i++) { 
        if (bought[i]){
            System.out.print(need[i] + " "); 
        }
    }
    System.out.println(" ");