sys*_*out 15 python list-comprehension
有这样的列表:
['foo','spam','bar']
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是否有可能使用列表理解来获得此列表作为结果?
['foo','ok.foo', 'spam', 'ok.spam', 'bar', 'ok.bar']
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unu*_*tbu 31
In [67]: alist = ['foo','spam', 'bar']
In [70]: [prefix+elt for elt in alist for prefix in ('','ok.') ]
Out[70]: ['foo', 'ok.foo', 'spam', 'ok.spam', 'bar', 'ok.bar']
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