Hél*_*éna 5 python forms django
我有一个表单,在输入信息后,根据信息过滤数据库并进行一些计算,最后将结果显示给重定向的URL.
我确实可以重定向到另一个URL并成功显示结果.但问题在于它无法显示用户提交的任何数据,只显示每个字段的内容,结果不是基于fitered queryset.让我们说总和,它只是总结数据库中的所有列,而不使用过滤结果.
我怀疑查询集没有将过滤后的结果传递给def get_context_data,因此get_context_data中的查询集不起作用.
如果你解开我的疑问,真的非常感谢你.
(我根据建议合并了2个类的EDIT版本,希望有人能纠正这个EDIT版本,谢谢)
urls.py
url(r'^result_list/$',ResultView.as_view(),name='result'),
url(r'^input/$',InputFormView.as_view(),name='input'),
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views.py
class InputFormView(request):
#class InputFormView(FormView):
template_name = 'inputform.html'
form_class = InputForm
response = HttpResponse( 'result' )
request_form_data = request.POST #you need to sanitize/clear this data
response.set_cookie('form_data', request_form_data)
#redirect to result page with submitted form information
def get_success_url(self):
return ''.join(
[
reverse('result'),
'?company=',self.request.POST.get('company'), <--do I need to change "POST" into "USER"?
'®ion=',self.request.POST.get('region')
]
)
#class ResultView(ListView):
class ResultView(request):
context_object_name = 'result_list'
template_name = 'result_list.html'
model = Result
def get_context_data(self, **kwargs):
context = super(ResultView, self).get_context_data(**kwargs)
context["sales"] = self.get_queryset().aggregate(Sum('sales'))
context["company"] = self.request.POST.get("company")
context["region"] = self.request.POST.get("region")
return context
def get_queryset(self):
if self.request.method == 'POST':
form = InputForm(self.request.POST)
if form.is_valid():
company = form.cleaned_data['company']
region = form.cleaned_data['region']
queryset=Result.objects.filter(region=region)
return queryset
return Result.objects.all()
if request.COOKIES.has_key('form_data'):
value = request.COOKIES['form_data'] #this data also should be sanitized
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HTML
<div class="basicinfo"> <!--Entry Form information submitted by user-->
<table border="1" cellpadding="1">
<tr>
<td align="left">Company</td>
<td>{{ company }}</td>
</tr>
<tr>
<td align="left">Region</td>
<td>{{ region }}</td>
</tr>
</table>
</div>
<!--Showing the filtered result in database-->
<td><table border="0" cellspacing="10" cellpadding="10">
<tr><b>Sales</b></tr>
<td bgcolor="#F0F0F0"> {{ sales.sales__sum }}</td>
</tr>
<tr><b>Employee</b></tr>
<tr>
<td bgcolor="#F0F0F0"> {{ employee.employee__sum }}</td>
</table>
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编辑 - 结合2类视图
import urllib
#@csrf_exempt
class ResultView(ListView):
context_object_name = 'result_list'
template_name = 'result_list.html'
model = Result
def get_queryset(self):
form = InputForm(self.request.GET)
if form.is_valid():
company = form.cleaned_data['company']
region = form.cleaned_data['region']
queryset=Result.objects.filter(region=region)
return queryset
return Result.objects.all()
def get_success_url(self):
params = {
'company': self.request.POST.get('company'),
'region': self.request.POST.get('region')
}
return ''.join([reverse('result'), '?', urllib.urlencode(params.items())])
def get_context_data(self,**kwargs):
context = super(ResultView, self).get_context_data(**kwargs)
context["sales"] = self.get_queryset().aggregate(Sum('sales'))
context["company"] = self.request.GET.get("company")
context["region"] = self.request.GET.get("region")
return context
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**EDIT- urls.py**
url(r'^result_list/$',ResultView.as_view(),name='result'),----for the result page
url(r'^input/$',result.views.get_success_url,name='input') -----for the form, I am not sure if this line correct or not?
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如果您将get_queryset方法更改为:您的代码应该可以工作:
def get_queryset(self):
# You are sending GET params here, not POST
form = InputForm(self.request.GET)
if form.is_valid():
company = form.cleaned_data['company']
region = form.cleaned_data['region']
queryset=Result.objects.filter(region=region)
return queryset
return Result.objects.all()
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以及您的get_context_data方法:
def get_context_data(self, **kwargs):
context = super(ResultView, self).get_context_data(**kwargs)
context["sales"] = self.get_queryset().aggregate(Sum('sales'))
# Your variables are in GET, not POST
context["company"] = self.request.GET.get("company")
context["region"] = self.request.GET.get("region")
return context
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也就是说,您的代码可以进行一些重构。您真的需要FormView接受 POST 请求吗?您可以使用一个通过 GET 直接提交到结果视图的表单。
使用您当前的方法,您实际上会处理表单两次 - 每个视图一次。
编辑:此外,您生成重定向网址的方式并不安全。你应该这样:
import urllib
def get_success_url(self):
params = {
'company': self.request.POST.get('company'),
'region': self.request.POST.get('region')
}
return ''.join([reverse('result'), '?', urllib.urlencode(params.items())])
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