如何在laravel 4.2中使用带有自定义预过滤器的AJAX上传CSV文件

Question

我正在使用laravel 4.2,目前我不知道如何public\csv\使用AJAX 将csv文件保存到目录中.我还在寻找一些答案.也许有人可以帮助我.

这是我的代码:

在刀片视图中:

 {{Form::open(['route' => 'file_upload', 'files' => true, 'id' => 'upload_form', 'method' => 'POST'])}}
    {{Form::file('csv_upload', ['id' => 'uploaded_file', 'accept' => 'text/csv'])}}
    {{Form::submit('submit', ['class' => 'btn btn-primary btn-xs', 'id' => 'upload'])}}
 {{Form::close()}}

Javascript Ajax:

var ajax_ready = 1
var token = {{Session::get('_token')}}

if($.type(originalOptions.data) === 'string') {
              options.data = originalOptions.data+"&_token="+token;
 }else if($.type(originalOptions.data) === 'object') {
         //Here I got a new error
 }else{
     options.data = $.param(($.extend(originalOptions.data, {'_token':mmad_token})));
 }

 options.url = originalOptions.url.slice(0,originalOptions.url.indexOf("?_token="));

   if (ajax_ready!=1){
              jqXHR.abort();
   }
  ajax_ready = 0;
});
$('form#upload_form').on('submit', function(e){
    e.preventDefault();
    var uploadFile =  $('#uploaded_file');

    var ext = $("input#uploaded_file").val().split(".").pop().toLowerCase();
    var file = $('input[name="csv_upload"]').val();

    if($.inArray(ext, ["csv"]) === -1) {
             alert("Please upload a .csv file!");
             return false;
    }

     var csv = uploadFile[0].files;
     var form = new FormData(this);

     var csvFile = {lastModifed: csv[0].lastModified, fileName: csv[0].name, size: csv[0].size, fileType: csv[0].type};

      $.post('{{ URL::route("file_upload") }}?_token={{Session::token()}}',{
           data: form
      }).done(function(response){

      });

});

PHP:

public function upload_csv()
{
    $inputs = Input::all();

    $csvFile = $inputs['data']['fileName'];

    $path = public_path().DIRECTORY_SEPARATOR.'csv'.DIRECTORY_SEPARATOR;
    $path2 = public_path('csv/');

    if(is_dir($path2))
    {
        @move_uploaded_file($csvFile, $path2.$csvFile); //This line can't move the uploaded files in my desired directory
    }

    return json_encode(['success' => 1, 'description' => 'Successfully Upload File']);

}

不使用AJAX时,下面的代码可以正常工作:

  if(Input::hasFile('csv_upload'))
    {
        $file = Input::file('csv_upload');

        $originalFilename = $file->getClientOriginalName();

        $rules = ['csv_upload' => 'required|file:csv'];

        $validate = Validator::make(['csv_upload' => $file], $rules);

        if($validate->fails())
        {
            return json_encode(['error' => 1, 'description' => 'File must be in .csv format']);
        }

        $path = public_path('/csv/');

        if(!file_exists($path))
        {
            mkdir($path);
        }
     }

Console.log的csv

Answer 1

您无法移动文件,因为当您使用ajax 文件提交表单时没有使用ajax发送,对于发送文件,您必须使用FormData() javascript对象发送文件.

如果您upload_csv通过放置检查控制器print_r($_FILES);将获得空阵列.

因此,在客户端使用FormData来附加文件,然后尝试使用agian.你没有得到错误,因为你使用php 错误控制运营商喜欢@move_uploaded_file($csvFile, $path2.$csvFile);.

如果你需要工作的例子然后告诉我,我会把它给你.

代码为您的帮助:1.在刀片视图中:

  <script type="text/javascript">
     $('form#upload_form').on('submit', function(e){
        e.preventDefault();
        var uploadFile =  $('#uploaded_file');

        var ext = $("input#uploaded_file").val().split(".").pop().toLowerCase();
        var file = $('input[name="mmad_csv_upload"]').val();

        if($.inArray(ext, ["csv"]) === -1) {
                 alert("Please upload a .csv file!");
                 return false;
        }
        var csv = uploadFile[0].files;
        var formData = new FormData($(this)[0]);
        formData.append('uploaded_file', $("#uploaded_file")[0].files[0]);
        formData.append('lastModifed', csv[0].lastModified);
        formData.append('fileName', csv[0].name);
        console.log(formData);


        $.ajax({
        url: '{{ URL::route("file_upload") }}',
        type: 'POST',
        data: formData,
        async: true,
        cache: false,
        contentType: false,
        processData: false,
        success: function (returndata) { //alert(returndata); return false;

        }
        });      

    });
 </script>

2.Controller

public function file_upload(Request $request)
{
    $inputs = Input::all();
    $csvFile = $inputs['fileName'];


    $path = public_path().DIRECTORY_SEPARATOR.'csv'.DIRECTORY_SEPARATOR;
    $path2 = public_path('/csv/');
    if(is_dir($path2))
    {
        $success = $request->file('uploaded_file')->move($path2, $csvFile);
    }
    return json_encode(['success' => 1, 'description' => 'Successfully Upload File']);

}

Answer 2

要将上传的文件移动到新位置，您应该使用 move 方法。此方法会将文件从其临时上传位置（由您的 PHP 配置确定）移动到您选择的更永久的目的地：

Input::file('fileName')->move($destinationPath, $fileName);

如果您需要额外的验证，可以在http://laravel.com/docs/5.1/requests#files进行检查