den*_*ero 1 javascript regex validation jquery parsley.js
问题
我在为Parsley.js插件创建自定义验证程序时遇到问题。我想做的是测试值与正则表达式。具体来说,我正在尝试验证密码值至少包含一个大写字母和一个小写字母。验证代码将引发错误,但在满足条件时不会返回true。
的HTML
<form name="Form" id="signupform" method="post" action="#" data-parsley-validate data-parsley-excluded="input[type=button], input[type=submit], input[type=reset], input[type=hidden], [disabled], :hidden">
<label for="password1">New Password <span class="req">*</span></label>
<input name="password" id="password1" type="password" class="password" data-parsley-minlength="1" data-parsley-errors-container=".errorspannewpassinput" data-parsley-required-message="Please enter your new password." data-parsley-mixedcase="^(?=.*[a-z])(?=.*[A-Z]).*$" data-parsley-required/>
<span class="errorspannewpassinput"></span>
<label for="confirm_password1">Confirm Password <span class="req">* </span></label>
<input name="Password_2" id="password2" type="password" class="password" data-parsley-minlength="1" data-parsley-errors-container=".errorspanconfirmnewpassinput" data-parsley-required-message="Please re-enter your new password." data-parsley-equalto="#password1" data-parsley-mixedcase="^(?=.*[a-z])(?=.*[A-Z]).*$" data-parsley-required />
<span class="errorspanconfirmnewpassinput"></span>
<input type="submit" name="submitinfo" id="submitsignup" data-theme="b" style="width:100%;" alt="Sign Up Now" value="Submit Account Request" />
</form>
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jQuery的
$(function() {
// Set variables
var pmixedCase = 'Y';
var mixedCase = $('.mixedcase');
var passwordField = $('#password1, #password2');
var passwordFieldErrors = $('.errorspannewpassinput, .errorspanconfirmnewpassinput');
// Assemble list of visible password requirements
// Mixed Case
if (pmixedCase === 'Y') {
mixedCase.show();
} else {
mixedCase.hide();
}
// Custom Validators
window.Parsley.addValidator('mixedcase', {
requirementType: 'regexp',
validateString: function(value, requirement) {
return requirement.test(value);
},
messages: {
en: 'Your password must contain at least (1) lowercase and (1) uppercase letter.'
}
});
});
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我在下面包括了一个JSFiddle。
您面临的问题是您的JsFiddle使用的是Parsley 2.1.2,而文档已更新为Parsley 2.2.0。
如果您查看Javascript控制台,将会看到错误:
未捕获的TypeError:window.Parsley.addValidator不是函数
这表示您使用的版本尚未更新(以前使用的版本window.ParsleyValidator.addValidator)。因此,如果您只是将Parsley.js更新到正确的版本,则代码将起作用。看到这个小提琴。
但是,有一种更简单的方法来完成您需要的操作(即没有自定义验证器)。您可以使用内置的模式(data-parsley-pattern)。例如:
<form name="Form" id="signupform" method="post" data-parsley-validate data-parsley-excluded="input[type=button], input[type=submit], input[type=reset], input[type=hidden], [disabled], :hidden">
<label for="password1">New Password <span class="req">*</span></label>
<input name="password" id="password1" type="password" class="password" data-parsley-minlength="1" data-parsley-errors-container=".errorspannewpassinput" data-parsley-required-message="Please enter your new password." data-parsley-pattern="(?=.*[a-z])(?=.*[A-Z]).*" data-parsley-pattern-message="Your password must contain at least (1) lowercase and (1) uppercase letter." data-parsley-required />
<span class="errorspannewpassinput"></span>
<label for="confirm_password1">Confirm Password <span class="req">*</span></label>
<input name="Password_2" id="password2" type="password" class="password" data-parsley-minlength="1" data-parsley-errors-container=".errorspanconfirmnewpassinput" data-parsley-required-message="Please re-enter your new password." data-parsley-equalto="#password1" data-parsley-pattern="(?=.*[a-z])(?=.*[A-Z]).*" data-parsley-required data-parsley-pattern-message="Your password must contain at least (1) lowercase and (1) uppercase letter."/>
<span class="errorspanconfirmnewpassinput"></span>
<input type="submit" name="submitinfo" id="submitsignup" data-theme="b" style="width:100%;" alt="Sign Up Now" value="Submit Account Request" />
</form>
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我改变了什么:
替换data-parsley-mixedcase="^(?=.*[a-z])(?=.*[A-Z]).*$"为data-parsley-pattern="(?=.*[a-z])(?=.*[A-Z]).*"两个输入。
根据Marc-AndréLafortune的评论,我删除了^开头和$结尾的,因为现在已经固定了模式。
data-parsley-pattern-message="Your password must contain at least (1) lowercase and (1) uppercase letter."在两个输入上均已添加。JsFiddle 在这里可用。
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