Spring Data MongoDB在"in"查询中失败

mat*_*rix 6 spring mongodb spring-data-mongodb

我正在使用spring-data-mongodb 1.8.0; MongoDB 3.0.6; mongo-java-driver 3.1.0; spring-framework.version 4.0.3.

我想要的是查询user某些电话号码列表.用户示例:{ "_id" : ObjectId("5625e5c32e1ca013a03f0d1b"), "phone" : "12345535"}

在Mongo Shell db.user.find({phone: { $in: [ "12345535", "123535"]}})工作正常.但在春天我失败了.Java类用户(省略了getter/setter):

@Document(collection = "user")
public class User {
    @Id
    String id;
    String phone;
}
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我尝试的是:

Query q = new Query(Criteria.where("phone").in("12345535","123535"));
mongoTemplate.find(q, User.class);
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它出现了错误:

Exception in thread "main" java.lang.IllegalAccessError: tried to access class org.springframework.beans.PropertyMatches from class org.springframework.data.mapping.PropertyReferenceException
    at org.springframework.data.mapping.PropertyReferenceException.detectPotentialMatches(PropertyReferenceException.java:134)
    at org.springframework.data.mapping.PropertyReferenceException.<init>(PropertyReferenceException.java:59)
    at org.springframework.data.mapping.PropertyPath.<init>(PropertyPath.java:75)
    at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:327)
    at org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:307)
    at org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:270)
    at org.springframework.data.mongodb.core.convert.QueryMapper$MetadataBackedField.getPath(QueryMapper.java:837)
    at org.springframework.data.mongodb.core.convert.QueryMapper$MetadataBackedField.<init>(QueryMapper.java:729)
    at org.springframework.data.mongodb.core.convert.QueryMapper$MetadataBackedField.with(QueryMapper.java:740)
    at org.springframework.data.mongodb.core.convert.QueryMapper$MetadataBackedField.with(QueryMapper.java:686)
    at org.springframework.data.mongodb.core.convert.QueryMapper.getMappedKeyword(QueryMapper.java:258)
    at org.springframework.data.mongodb.core.convert.QueryMapper.getMappedObjectForField(QueryMapper.java:200)
    at org.springframework.data.mongodb.core.convert.QueryMapper.getMappedObject(QueryMapper.java:123)
    at org.springframework.data.mongodb.core.MongoTemplate.doFind(MongoTemplate.java:1700)
    at org.springframework.data.mongodb.core.MongoTemplate.doFind(MongoTemplate.java:1690)
    at org.springframework.data.mongodb.core.MongoTemplate.find(MongoTemplate.java:602)
    at org.springframework.data.mongodb.core.MongoTemplate.find(MongoTemplate.java:593)
    at com.example.TestMongo.main(TestMongo.java:30)
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但是通过将现场电话更改为id,相同的代码工作正常.

Query q = new Query(Criteria.where("id").in("5625e5c32e1ca013a03f0d1b","f0d1e"));
mongoTemplate.find(q, User.class);
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通过调试,我发现它甚至没有进入请求阶段,在查询构建阶段发生了错误.它似乎$in无法处理PropertyPath.create,而在这种id情况下,它可以.

我怎样才能解决这个问题?我是一个新手,搜索了很多但没有运气.可以帮助我.每个答案都表示赞赏.多谢你们.

Oli*_*ohm 11

正如公告博客发布系列wiki所示,Spring Data MongoDB 1.8需要Spring 4.1,理想情况下4.1.8包含一个重要的安全修复程序.

  • Spring 4.1.5仍然存在与MongoDB 1.8.1相同的问题,但切换到Spring 4.1.8对我有用.(Spring 4.1.8.RELEASE + Spring MongoDB 1.8.1) (2认同)