编写一个循环来创建具有不同数据源和标题的ggplot数字

Question

我没有循环经验,但看起来我需要创建一些来正确分析我的数据.你能说明如何在我已经创建的代码上创建一个简单的循环吗？让我们使用循环来获得一些图:

pdf(file = sprintf("complex I analysis", tbl_comp_abu1), paper='A4r')

ggplot(df_tbl_data1_comp1, aes(Size_Range, Abundance, group=factor(Gene_Name))) +
  theme(legend.title=element_blank()) +
  geom_line(aes(color=factor(Gene_Name))) +
  ggtitle("Data1 - complex I")+
  theme(axis.text.x = element_text(angle = 90, hjust = 1))

ggplot(df_tbl_data2_comp1, aes(Size_Range, Abundance, group=factor(Gene_Name))) +
  theme(legend.title=element_blank()) +
  geom_line(aes(color=factor(Gene_Name))) +
  ggtitle("Data2 - complex I")+
  theme(axis.text.x = element_text(angle = 90, hjust = 1))


ggplot(df_tbl_data3_comp1, aes(Size_Range, Abundance, group=factor(Gene_Name))) +
  theme(legend.title=element_blank()) +
  geom_line(aes(color=factor(Gene_Name))) +
  ggtitle("Datas3 - complex I")+
  theme(axis.text.x = element_text(angle = 90, hjust = 1))

dev.off()

现在的问题是我想要实现的目标.首先,我想要分析10个复合体,这意味着应该创建10个pdf文件,并且该示例显示了复杂的三个不同数据集的图.为了使其正确,变量comp1(from df_tbl_dataX_comp1)中的数字必须从1更改为10 - 取决于我们想要绘制的复数.必须通过循环更改的下一件事是pdf文件的名称和每个图...是否可以编写这样的循环？

数据:

structure(list(Size_Range = structure(c(1L, 1L, 1L, 2L, 2L, 2L, 
3L, 3L, 3L, 4L, 4L, 4L, 5L, 5L, 5L, 6L, 6L, 6L, 7L, 7L, 7L, 8L, 
8L, 8L, 9L, 9L, 9L, 10L, 10L, 10L, 11L, 11L, 11L, 12L, 12L, 12L, 
13L, 13L, 13L, 14L, 14L, 14L, 15L, 15L, 15L, 16L, 16L, 16L, 17L, 
17L, 17L, 18L, 18L, 18L, 19L, 19L, 19L, 20L, 20L, 20L), .Label = c("10", 
"34", "59", "84", "110", "134", "165", "199", "234", "257", "362", 
"433", "506", "581", "652", "733", "818", "896", "972", "1039"
), class = "factor"), Abundance = c(0, 0, 0, 0, 0, 0, 0, 0, 0, 
0, 0, 0, 0, 0, 0, 0, 0, 142733.475, 108263.525, 98261.11, 649286.165, 
3320759.803, 3708515.148, 6691260.945, 30946562.92, 180974.3725, 
4530005.805, 21499827.89, 0, 15032198.54, 4058060.583, 0, 3842964.97, 
2544030.857, 0, 1640476.977, 286249.1775, 0, 217388.5675, 1252965.433, 
0, 1314666.05, 167467.8825, 0, 253798.15, 107244.9925, 0, 207341.1925, 
15755.485, 0, 71015.85, 14828.5075, 0, 25966.2325, 0, 0, 0, 0, 
0, 0), Gene_Name = c("AT1G01080", "AT1G01090", "AT1G01320", "AT1G01420", 
"AT1G01470", "AT1G01560", "AT1G01800", "AT1G02150", "AT1G02500", 
"AT1G02560", "AT1G02780", "AT1G02880", "AT1G02920", "AT1G02930", 
"AT1G03030", "AT1G03090", "AT1G03110", "AT1G03130", "AT1G03220", 
"AT1G03230", "AT1G03330", "AT1G03475", "AT1G03630", "AT1G03680", 
"AT1G03870", "ATCG00420", "ATCG00470", "ATCG00480", "ATCG00490", 
"ATCG00500", "ATCG00650", "ATCG00660", "ATCG00670", "ATCG00740", 
"ATCG00750", "ATCG00842", "ATCG01100", "ATCG01030", "ATCG01114", 
"ATCG01665", "ATCG00770", "ATCG00780", "ATCG00800", "ATCG00810", 
"ATCG00820", "ATCG00722", "ATCG00744", "ATCG00855", "ATCG00853", 
"ATCG00888", "ATCG00733", "ATCG00766", "ATCG00812", "ATCG00821", 
"ATCG00856", "ATCG00830", "ATCG00900", "ATCG01060", "ATCG01110", 
"ATCG01120")), .Names = c("Size_Range", "Abundance", "Gene_Name"
), row.names = c(NA, -60L), class = "data.frame")

Answer 1

这可能会起作用：启动两个循环，一个用于复杂迭代，第二个用于数据集迭代。然后使用paste0()或paste()生成正确的文件名和标题。

PS：我没有测试代码，因为我没有你的数据。但它应该给你一个想法。

#loop over complex    
for (c in 1:10) {

    #create pdf for every complex 
    pdf(file = paste0("complex", c, "analysis.pdf"), paper='A4r')

    #loop over datasets
    for(d in 1:3) {

    #plot
    ggplot(get(paste0("df_tbl_data",d,"_comp",c)), aes(Size_Range, Abundance, group=factor(Gene_Name))) +
      theme(legend.title=element_blank()) +
      geom_line(aes(color=factor(Gene_Name))) +
      ggtitle(paste0("Data",d," - complex ",c))+
      theme(axis.text.x = element_text(angle = 90, hjust = 1))
    }   
    dev.off()

}