同时阅读3个选定项目

Question

如何在同一时间阅读3个微调器选定的项目？我spinner1,2,3在WorkDetails.java和他们的价值已经被插入SQLite.在我UpdatePage.java,我想要检索所选项目,所选项目应首先显示在微调器中project1,project2 and project3.

UpdatePage.java

public void RetrievePage(String name,String date, String id) {
    final String name2 = name;
    final String date2=date;
    final String id2 = id;
    final EditText name3 = (EditText) findViewById(R.id.editText9);
    final EditText date3 = (EditText) findViewById(R.id.editText12);
    name3.setText(name2);
    date3.setText(date2);

    database = dbHelper.getWritableDatabase();
    c = database.rawQuery(
        "SELECT i.Weather, i.Status,w.Subcontractors, w.NumberOfPerson,"+
        "w.NumberOfHours, wd.Project, wd.WorkDescription, wd.Per,"+
        "wd.TimeIn, wd.TimeOut FROM Information i LEFT JOIN WorkForce w "+
        "ON w.TInfo_id = i._id "+
        "LEFT JOIN WorkDetails wd ON wd.Twf_id=w._id "+
        "WHERE i.Name = ? AND i._id= ? ",
        new String[]{String.valueOf(name2),String.valueOf(id2)}, null);
    if (c != null) {
        while (c.moveToNext()) {
            Details WD = new Details();
            String Project11 = c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));
            String Project22  =c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));
            String Project33  =c.getString(c.getColumnIndexOrThrow(MyDatabaseHelper.Project));

            addProject1(Project11);
            addProject2(Project22);
            addProject3(Project33);
            WD.setProject(Project11);
            WD.setProject(Project22);
            WD.setProject(Project33);
        }
    }
    c.close();
}

public void addProject1(String l) {
    project1 = (Spinner) findViewById(R.id.spinner8);
    String[] arr = new String[]{"1","2","3"};
    List<String> list = new ArrayList<String>();
    String project11 = l;
    list.add(project11);
    for (String s : arr) {
        if (!list.contains(s)) {
            list.add(s);
        }
    }
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(UpdatePage.this, android.R.layout.simple_spinner_dropdown_item, list);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    project1.setAdapter(adapter);
}

public void addProject2(String d) {
    project2 = (Spinner)findViewById(R.id.spinner9);
    String[] arr = new String[]{"1","2","3"};
    List<String> list = new ArrayList<String>();
    String project22 = d;
    list.add(project22);
    for (String s:arr) {
        if(!list.contains(s)) {
            list.add(s);
        }
    }
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(UpdatePage.this, android.R.layout.simple_spinner_dropdown_item, list);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    project2.setAdapter(adapter);
}

public void addProject3(String e) {
    project3 = (Spinner)findViewById(R.id.spinner13);
    String[] arr = new String[]{"1","2","3"};
    List<String> list = new ArrayList<String>();
    String project33 = e;
    list.add(project33);
    for (String s:arr) {
        if (!list.contains(s)) {
            list.add(s);
        }
    }
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(UpdatePage.this, android.R.layout.simple_spinner_dropdown_item, list);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item);
    project3.setAdapter(adapter);
}

假设spinner1保持值1,spinner2保持2并spinner3保持3.当来到时updatePage,微调器project1应首先显示1,project2显示2,依此类推.但问题现在是project1,2,并且3显示值1首先...我怎样才能实现这一目标？

Answer 1

为此，您可以尝试一些逻辑

从数据库中获取三个值。别理他们

selected_value_of_spinner1, selected_value_of_spinner2,selected_value_of__spinner3

然后定义你的方法getPosition如下

public int getPosition(Spinner your_spinner, String string_value){

    int position = 0;

    for (int i=0;i<your_spinner.getCount();i++){
        if (your_spinner.getItemAtPosition(i).equals(string_value)){
            position = i;
        }
    }
    return position;
    }

显示从旋转器中的数据库获取的值，如下所示

your_spinner1.setSelection(getPosition(your_spinner1, selected_value_of_spinner1));
your_spinner2.setSelection(getPosition(your_spinner2, selected_value_of_spinner2));
your_spinner3.setSelection(getPosition(your_spinner3, selected_value_of_spinner3));

基本上这里发生的是

1. 您从数据库中获取值

2. 您可以匹配从微调器中的数据库获取的值，以通过getPosition()方法获取其在微调器中的位置。

3. 根据通过setSelection(position)方法从步骤 2 获得的位置设置微调器值。