使用复选框过滤谷歌地图标记

Question

我试图根据此V3示例从复选框中过滤我的谷歌地图标记.我的复选框html是:

<form action="#">
  Attractions: <input type="checkbox" id="attractionbox" onclick="boxclick(this,'attraction')" /> &nbsp;&nbsp;
  Food and Drink: <input type="checkbox" id="foodbox" onclick="boxclick(this,'food')" /> &nbsp;&nbsp;
  Hotels: <input type="checkbox" id="hotelbox" onclick="boxclick(this,'hotel')" /> &nbsp;&nbsp;
  Towns/Cities: <input type="checkbox" id="citybox" onclick="boxclick(this,'city')" /><br />
</form>

我的javascript在下面.我似乎无法使过滤器工作 - 目前所有标记都出现在地图上,无论复选框的状态如何.我猜我在错误的地方得到了一些变量,但到目前为止我还没能解决问题!任何帮助将非常感激.

var map;
var infowindow;
var image = [];
var gmarkers = [];

  image['attraction'] = 'http://google-maps-icons.googlecode.com/files/beach.png'; 
  image['food'] = 'http://google-maps-icons.googlecode.com/files/restaurant.png';
  image['hotel'] = 'http://google-maps-icons.googlecode.com/files/hotel.png';
  image['city'] = 'http://google-maps-icons.googlecode.com/files/smallcity.png';

function mapInit(){
    var centerCoord = new google.maps.LatLng(18.23, -66.39); 
    var mapOptions = {
        zoom: 1,
        center: centerCoord,
        mapTypeId: google.maps.MapTypeId.ROADMAP
    };

    map = new google.maps.Map(document.getElementById("map"), mapOptions);

    google.maps.event.addListener(map, 'click', function() {
      infowindow.close();
    });

    jQuery.getJSON("/places", function(json) {
      if (json.length > 0) {
        for (i=0; i<json.length; i++) {
          var place = json[i];
          var category = json[i].tag;
          addLocation(place,category);
        }
      }
    });

    function addLocation(place,category) {
      var marker = new google.maps.Marker({
        position: new google.maps.LatLng(place.lat, place.lng),
        map: map,
        title: place.name,
        icon: image[place.tag]
      });

      marker.mycategory = category;
      gmarkers.push(marker);

      google.maps.event.addListener(marker, 'click', function() {
        if (infowindow) infowindow.close();
        infowindow = new google.maps.InfoWindow({
          content: "<h3>"+ place.name +"</h3><p>" + place.tag +"</p><a href='/places/"+place.id+"'>Show more!</a>"
        });
        infowindow.open(map, marker);
      });
    }

    function show(category) {
      for (var i=0; i<gmarkers.length; i++) {
        if (gmarkers[i].mycategory == category) {
          gmarkers[i].setVisible(true);
        }
      }
      document.getElementById(category+"box").checked = true;
    }

    function hide(category) {
      for (var i=0; i<gmarkers.length; i++) {
        if (gmarkers[i].mycategory == category) {
          gmarkers[i].setVisible(false);
        }
      }
      document.getElementById(category+"box").checked = false;
      infowindow.close();
    }

    function boxclick(box,category) {
      if (box.checked) {
        show(category);
      } else {
        hide(category);
      }
    }
}

jQuery(document).ready(function(){
    mapInit();
});

Answer 1

您的问题是该boxclick()函数包含在函数的范围内mapInit(),因此boxclick()无法从外部访问mapInit().您应该onclick从HTML输入字段中删除事件,然后在mapInit()函数中定义事件处理程序,如下所示:

function mapInit() {

  // ...

  $('#attractionbox').click(function () {
    boxclick(this, 'attraction');
  }); 
}