通过HttpResponse Java下载Zip文件

Question

所以我从一个数据库(各种mimetypes)抓取一个blob集合,并试图将它们压缩起来,由用户通过http响应下载.我可以进行下载,但是当我尝试打开下载的zip文件时,它说"存档格式未知或已损坏".我已经尝试了以下代码与application/zip,application/octet-stream和application/x-zip-compressed,但我开始假设问题在于我如何添加文件.我也使用Java 7和Grails 2.2.4.

任何有关这方面的帮助将不胜感激.谢谢!

  final ZipOutputStream out = new ZipOutputStream(new FileOutputStream("test.zip"));


        for (Long id : ids){

            Object[] stream = inlineSamplesDataProvider.getAttachmentStream(id);


            if (stream) {

                String fileName = stream[0]
                String mimeType = (String) stream[1];
                InputStream inputStream = stream[2]
                byte[] byteStream = inputStream.getBytes();

                ZipEntry zipEntry = new ZipEntry(fileName)
                out.putNextEntry(zipEntry);
                out.write(byteStream, 0, byteStream.length);
                out.closeEntry();
            }
        }

        out.close();
        response.setHeader("Content-Disposition", "attachment; filename=\"" + "test.zip" + "\"");
        response.setHeader("Content-Type", "application/zip");
        response.outputStream << out;
        response.outputstream.flush();

Answer 1

我在这里找到了答案:将ZipOutputStream返回给浏览器

好吧,最终为我工作的是将ZipOutputStream转换为ByteArrayOutputStream并将其作为byte []写入响应:

ZipOutputStream to a ByteArrayOutputStream and writing it to a response as a byte[]:
ByteArrayOutputStream baos = new ByteArrayOutputStream();
final ZipOutputStream out = new ZipOutputStream(baos);

Calendar cal = Calendar.getInstance();
String date = new SimpleDateFormat("MMM-dd").format(cal.getTime());

final String zipName = "COA_Images-" + date + ".zip";

for (Long id: ids) {

    Object[] stream = inlineSamplesDataProvider.getAttachmentStream(id);

    if (stream) {

        String fileName = stream[0];
        String mimeType = (String) stream[1];
        InputStream inputStream = stream[2];
        byte[] byteStream = inputStream.getBytes();

        ZipEntry zipEntry = new ZipEntry(fileName)
        out.putNextEntry(zipEntry);
        out.write(byteStream, 0, byteStream.length);
        out.closeEntry();
    }
}

out.close();

response.setHeader("Content-Disposition", "attachment; filename=\"" + zipName + "\"");
response.setHeader("Content-Type", "application/zip");
response.getOutputStream().write(baos.toByteArray());
response.flushBuffer();
baos.close();

感谢所有帮助过的人!