如 PostgreSQL手册中所述,可以在单个INSERT语句中添加多行:
INSERT INTO films (code, title, did, date_prod, kind) VALUES
('6717', 'Tampopo', 110, '1985-02-10', 'Comedy'),
('6120', 'The Dinner Game', 140, DEFAULT, 'Comedy');
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SELECT像这样的嵌套查询也有效:
INSERT INTO films (code, title, did, date_prod, kind)
SELECT table.code, 'Tampopo', 110, '1985-02-10', 'Comedy'
FROM other_table AS table2;
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但是,我似乎无法想出一种同时进行的方法:
INSERT INTO films (code, title, did, date_prod, kind)
SELECT
(table.code + 100, 'abc', NULL, t2.date_prod, t2.kind),
(table.code + 200, 'xyz', NULL, t2.date_prod, t2.kind)
FROM other_table AS t2;
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如果other_table只包含(61717 | 'Tampopo' | NULL | '1985-02-10' | 'Comedy'),结果表将如下所示:
code | title | did | date_prod | kind
--------------------------------------------------
61817 | 'abc' | NULL | '1985-02-10' | 'Comedy'
61917 | 'xyz' | NULL | '1985-02-10' | 'Comedy'
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这个小提琴应该进一步解释它......
你能不能指出我哪里出错了。如果可能的话,我想避免多次查找,other_table AS t2因为它是一个VIEW并且需要相当长的时间来构建。
一般来说,你可以使用select带union:
insert into films (code, title, did, date_prod, kind)
select t2.code + 100, t2.title, NULL::float, t2.date_prod, t2.kind
from other_table AS t2
union
select t2.code + 200, t2.title, NULL::float, t2.date_prod, t2.kind
from other_table AS t2;
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在您描述的特定情况下,您可以使用unnest (array []):
insert into films (code, title, did, date_prod, kind)
select
unnest(array[t2.code + 100, t2.code + 200]),
t2.title, NULL::float, t2.date_prod, t2.kind
from other_table AS t2
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您可以使用INSERT INTO ... UNION ALL:
INSERT INTO films (code, title, did, date_prod, kind)
SELECT t2.code + 100, t2.title, t2.did, t2.date_prod, t2.kind
FROM other_table AS t2
UNION ALL
SELECT t2.code + 200, t2.title, t2.did, t2.date_prod, t2.kind
FROM other_table AS t2;
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