akr*_*kik 3 latex tabular multirow
我有这张乳胶代码.
\begin{table}[c]
\caption{\textbf{the results of analysis of variance (One Way ANOVA)
for the differences in the responses of the study sample according
to different classes.}}
\bigskip
\centering
\begin{tabular} {|M{4.5cm}|M{1.5cm}|M{1.5cm}|M{1.5cm}|M{1.75cm}|M{1.5cm}|M{2.5cm}|}
\hline
\textbf{} & \textbf{Variance}
&\textbf{Sum of the squares } & \textbf{Degrees of Freedom } &
\textbf{Average Squares} &\textbf{P Value} &\textbf{Statistical significance } \\
\hline
\multirow{3}{*}{\makecell{Q11.2}} & UK &122 & 0.14 & 0.348 &
\multirow{3}{*}{\makecell{0.978} } & \multirow{3}{*}
{\makecell{0.329}}\\ \cline{2-5}
& SA & 224 & 0.10 & 0.304
\\ \cline{2-5}
& SA & 224 & 0.10 & 0.304
&& \\ \hline
\end{tabular}
\end{table}
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我不知道如何填补空的垂直线!
我的代码出了什么问题?
使用时\multirow,您必须在希望多行跨越的每一行中包含空单元格.这意味着该行
& SA & 224 & 0.10 & 0.304 \\
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实际上应该读作
& SA & 224 & 0.10 & 0.304 & & \\
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这应该会给你想要的结果!
另外两个评论:
\makecell-command 的用法,我认为这不是必需的.\newcolumntype{M}[1]{>{\centering\arraybackslash}m{#1}}这是我使用的整个代码
\documentclass[a4paper,11pt]{article}
\usepackage[a4paper,text={160mm,255mm},centering,headsep=5mm,footskip=10mm]{geometry}
\usepackage[english]{babel}
\usepackage[utf8x]{inputenc}
\usepackage{array}
\usepackage{multirow}
\newcolumntype{M}[1]{>{\centering\arraybackslash}m{#1}}
\begin{document}
\begin{table}[c]
\caption{\textbf{the results of analysis of variance (One Way ANOVA)
for the differences in the responses of the study sample according
to different classes.}}
\bigskip
\centering
\begin{tabular}{|M{4.5cm}|M{1.5cm}|M{1.5cm}|M{1.5cm}|M{1.75cm}|M{1.5cm}|M{2.5cm}|}
\hline
& \textbf{Variance} & \textbf{Sum of the squares} &
\textbf{Degrees of Freedom } & \textbf{Average Squares} &
\textbf{P Value} & \textbf{Statistical significance } \\
\hline
\multirow{3}{*}{Q11.2} & UK &122 & 0.14 & 0.348 &
\multirow{3}{*}{0.978} & \multirow{3}{*}{0.329}\\
\cline{2-5}
& SA & 224 & 0.10 & 0.304 & & \\
\cline{2-5}
& SA & 224 & 0.10 & 0.304 & & \\
\hline
\end{tabular}
\end{table}
\end{document}
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