在jquery中查找当前可见的div

ACP*_*ACP 4 html jquery effects

我有四个div所有设置display:none和文件.我正在显示第一个div ..我有4个链接按钮link1,link2 ... link4 ...我在link1上显示div1点击等等..如何找到哪个div目前在jquery中可见?

 <style type="text/css">
        .ContentDivs
        {
            width: 90%;
            height: 300px;
            border: solid 5px #404040;
            display:none;
        }
    </style>
</head>
<body>
    <form id="form1" runat="server">
    <div>
        <div>
            <a id="Link1" href="#">Link1</a> 
            <a id="Link2" href="#">Link2</a>
             <a id="Link3" href="#">Link3</a> 
             <a id="Link4" href="#">Link4</a>
        </div>
        <div id="div1" class="ContentDivs">
        DIv1
        </div>
        <div id="div2" class="ContentDivs">
        Div2
        </div>
        <div id="div3" class="ContentDivs">
        Div3
        </div>
        <div id="div4" class="ContentDivs">
        Div4
        </div>
    </div>
    <script type="text/javascript">
        $(document).ready(function() {
              $("#div1").show().fadeIn("slow");
        });
        $('#Link1').click(function() {
        $(".ContentDivs").fadeOut("fast");//find current div here?
            $("#div1").show().fadeIn("slow");
        });
        $('#Link2').click(function() {
        $(".ContentDivs").fadeOut("fast");//find current div here?
            $("#div2").show().fadeIn("slow");
        });
        $('#Link3').click(function() {
        $(".ContentDivs").fadeOut("fast");//find current div here?
            $("#div3").show().fadeIn("slow");
        });
        $('#Link4').click(function() {
        $(".ContentDivs").fadeOut("fast");//find current div here?
            $("#div4").show().fadeIn("slow");
        });
    </script>
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http://jsbin.com/umode4/edit上查看效果

Rei*_*gel 5

用较小的代码,你可以这样做...

jQuery的

<script type="text/javascript">
    $(document).ready(function() {
          $("#div1").show().fadeIn("slow");
    });
    $('.links a').click(function() {
        $(".ContentDivs:visible").fadeOut("fast");//find current div here?
        $("#div" + ($(this).index()+1)).show().fadeIn("slow");
    });
</script>
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HTML

<div>
    <div class="links">
        <a id="Link1" href="#">Link1</a> 
        <a id="Link2" href="#">Link2</a>
        <a id="Link3" href="#">Link3</a> 
        <a id="Link4" href="#">Link4</a>
    </div>
    <div id="div1" class="ContentDivs">
        DIv1
    </div>
    <div id="div2" class="ContentDivs">
        Div2
    </div>
    <div id="div3" class="ContentDivs">
        Div3
    </div>
    <div id="div4" class="ContentDivs">
        Div4
    </div>
</div>
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演示