比较Python中的两个UTC时间戳

Question

我的数据有一个UTC时间戳字段作为字符串格式(例如'1426402510').我需要将此字段与当前时间进行比较,并以秒为单位发出持续时间.我不确定如何将此字符串转换为正确的日期时间格式进行转换 - 我在Python中使用不同的datetime方法的尝试产生了错误,所以我将非常感谢您的帮助.这是我的代码的一部分:

 import datetime

 # get current local time as a UTC timestamp
 current_time = datetime.datetime.utcnow()
 current_time.strftime("%s")

 # convert the string representing the UTC timestamp in my data to datetime for comparison
 time_val = '1426402510'
 #utc_dt = ??      # how should I convert time_val to compare with current_time?

 # the required output
 diff = (current_time - utc_dt).total_seconds()

谢谢你的帮助.

Answer 1

要将字符串转换为datetime对象,只需使用utcfromtimestamp调用int时间戳字符串即可.

import datetime

current_time = datetime.datetime.utcnow()
time_val = '1426402510'

diff = (current_time - datetime.datetime.utcfromtimestamp(int(time_val))).total_seconds()

print(diff)

Answer 2

要将当前时间作为"自纪元以来的秒数",请使用time.time():

#!/usr/bin/env python
import time

now = time.time()
then = int('1426402510')
print("Duration: %.0f seconds" % (now - then))

如果您需要使用datetime:

#!/usr/bin/env python3
from datetime import datetime, timedelta

now = datetime.utcnow()
then = datetime.utcfromtimestamp(int('1426402510'))
diff = (now - then) / timedelta(seconds=1)
print("Duration: %.0f seconds" % diff)

你可以timedelta.total_seconds()在Python 2上使用哪里/ timedelta不起作用.