如何将表单输入数组转换为PHP数组

Question

我有一个类似下面的表单发布到contacts.php,用户可以使用jquery动态添加更多.

<input type="text" name="name[]" />
<input type="text" name="email[]" />

<input type="text" name="name[]" />
<input type="text" name="email[]" />

<input type="text" name="name[]" />
<input type="text" name="email[]" />

如果我在PHP中用下面的代码回显它们

$name = $_POST['name'];
$email = $_POST['account'];

foreach( $name as $v ) {
print $v;
}

foreach( $email as $v ) {
print $v;
}

我会得到这样的东西:

name1name2name3email1email2email3

我怎样才能将这些数组变成类似下面的代码

function show_Names($n, $m)
{
return("The name is $n and email is $m, thank you");
}

$a = array("name1", "name2", "name3");
$b = array("email1", "email2", "email3");

$c = array_map("show_Names", $a, $b);
print_r($c);

所以我的输出是这样的:

名称是name1,email是email1,谢谢你
的名字是name2,email是email2,谢谢你
的名字是name3,email是email3,谢谢

感谢您的帮助或建议

Answer 1

它们已经在数组中:$name是一个数组,就是这样$email

所以你需要做的就是添加一些处理来攻击两个数组:

$name = $_POST['name'];
$email = $_POST['account'];

foreach( $name as $key => $n ) {
  print "The name is ".$n." and email is ".$email[$key].", thank you\n";
}

要处理更多输入,只需扩展模式:

$name = $_POST['name'];
$email = $_POST['account'];
$location = $_POST['location'];

foreach( $name as $key => $n ) {
  print "The name is ".$n.", email is ".$email[$key].
        ", and location is ".$location[$key].". Thank you\n";
}

Answer 2

例如,通过命名字段,如

<input type="text" name="item[0][name]" />
<input type="text" name="item[0][email]" />

<input type="text" name="item[1][name]" />
<input type="text" name="item[1][email]" />

<input type="text" name="item[2][name]" />
<input type="text" name="item[2][email]" />

(通过javascript添加元素时也可以)

相应的php脚本可能看起来像

function show_Names($e)
{
  return "The name is $e[name] and email is $e[email], thank you";
}

$c = array_map("show_Names", $_POST['item']);
print_r($c);