Kat*_*ina 4 objective-c uitableview ios
我有一个带有表视图的视图控制器.每个单元格都有一个带五星评级系统的自定义视图.我在视图的类中处理视图的touchesBegan
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
UITouch *touch = [touches anyObject];
CGPoint touchLocation = [touch locationInView:self];
[self handleTouchAtLocation:touchLocation];
}
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如何获取indexPath以了解哪个单元用户投票?我没有按钮我有uiview所以我不能使用以下内容:
CGPoint buttonPosition = [sender convertPoint:CGPointZero toView:self.tableView];
NSIndexPath *indexPath = [self.tableView indexPathForRowAtPoint:buttonPosition];
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iDe*_*per 10
做一件事
在索引路径的行中为单元格内的视图提供手势
UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(tappedOnView:)];
[singleTap setNumberOfTapsRequired:1];
[singleTap setNumberOfTouchesRequired:1];
[viewnanme addGestureRecognizer:singleTap];
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并处理轻拍手势
-(void)tappedOnView:(UITapGestureRecognizer *)gesture
{
CGPoint location = [gesture locationInView:tableView];
NSIndexPath *ipath = [tableView indexPathForRowAtPoint:location];
UITableViewCell *cellindex = [tableView cellForRowAtIndexPath: ipath];
}
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Swift 3+
var singleTap = UITapGestureRecognizer(target: self, action: #selector(self.tappedOnView))
singleTap.numberOfTapsRequired = 1
singleTap.numberOfTouchesRequired = 1
viewnanme.addGestureRecognizer(singleTap)
func tapped(onView gesture: UITapGestureRecognizer) {
let location: CGPoint = gesture.location(in: tableView)
let ipath: IndexPath? = tableView.indexPathForRow(at: location)
let cellindex: UITableViewCell? = tableView.cellForRow(at: ipath!)
}
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Swift 4+
var singleTap = UITapGestureRecognizer(target: self, action:
#selector(self.tappedOnView))
singleTap.numberOfTapsRequired = 1
singleTap.numberOfTouchesRequired = 1
viewnanme.addGestureRecognizer(singleTap)
func tapped(onView gesture: UITapGestureRecognizer)
{
let location: CGPoint = gesture.location(in: tableView)
let ipath: IndexPath? = tableView.indexPathForRow(at: location)
let cellindex: UITableViewCell? = tableView.cellForRow(at: ipath ??
IndexPath(row: 0, section: 0))
}
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希望这对你有所帮助.:)
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