根据值之一从元组列表中删除重复项

Question

我有一个格式列表(浮点数,字符串).如何从列表中删除具有相同浮点值的重复项？

列表按浮点顺序排序.我想保留订单.

[(0.10507038451969995,
  'Deadly stampede in Shanghai - Emergency personnel help victims.'),
 (0.078586381821416265,
  'Deadly stampede in Shanghai - Police and medical staff help injured people after the stampede.'),
 (0.072031446647399661, '- Emergency personnel help victims.'),
 (0.072031446647399661, 'Emergency personnel help victims.')]

看看最后两个.

Answer 1

您可以使用,itertools.groupby因为您已经对这些值进行了排序.这是数据:

>>> lot
[(0.10507038451969995, 'Deadly stampede in Shanghai - Emergency personnel help victims.'), 
(0.07858638182141627, 'Deadly stampede in Shanghai - Police and medical staff help injured people after the stampede.'), 
(0.07203144664739966, '- Emergency personnel help victims.'), 
(0.07203144664739966, 'Emergency personnel help victims.')]

示范:

>>> import itertools
>>> [next(t) for _, t in itertools.groupby(lot, lambda x: x[0])]
[(0.10507038451969995,
  'Deadly stampede in Shanghai - Emergency personnel help victims.'),
 (0.07858638182141627,
  'Deadly stampede in Shanghai - Police and medical staff help injured people after the stampede.'),
 (0.07203144664739966, '- Emergency personnel help victims.')]

这将为您提供组合在一起的第一个值.