在提交注册表单时使用jQuery显示错误

Question

我的最后一个问题不明确,所以我在这里发布了所有澄清.在下面的代码中,我想使用jQuery显示注册表单错误的错误消息.问题在于此代码只是将数据插入数据库而不检查任何错误或显示错误消息并重定向到登录页面.那么我哪里出错了？

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现在我已经更新了我的代码,除非所有条件都按照我的要求完成,但是没有提交数据,但是在点击提交按钮register.php时显示错误,页面重新加载,现在它只显示错误消息,没有注册表单,就像没有使用jQuery一样.我不希望重新加载页面它应该在那里显示错误消息.

<?php
if(isset($_POST['reg'])){
 $fn = ucfirst($_POST['fname']);
 $ln = ucfirst($_POST['lname']);
 $un = $_POST['username'];
 $em = $_POST['email'];
 $pswd = $_POST['password'];
 $pswd2 = $_POST['password2'];

 $sql=$db->prepare("SELECT username FROM users WHERE username=:username");
 $sql->execute(array(':username'=>$un));
 $row = $sql->fetch(PDO::FETCH_ASSOC);
 $db_username = $row['username'];
 $usernames = $db_username;

 $data = array();
 if( isset($fn) && isset($ln) ) {
  if( $fn != "" && $ln!="" && $fn == $ln ) {
    $data["flname"] = "cntbempty";
   }
  }
 if( isset($un) ) {
  if $un == $usernames )  {
    $data["username"] = "inuse";
   }
  }
 if( isset($pswd) && isset($pswd2) ) {
  if( $pswd2 != "" && $pswd != $pswd2 ) {
    $data["password"] = "missmatch";
   }
  }
  if( isset( $em ) ) {
   if( $em != "" && !preg_match( "/^([a-zA-Z0-9])+([a-zA-Z0-9\._-])*@([a-zA-Z0-9_-])+([a-zA-Z0-9\._-]+)+$/", $_POST["email"] ) ) {
     $data["email"] = "notvalid";
   }
  }
 if(!empty($data))
 {
 echo json_encode($data);
 die;
 }
  else{

  $pswd = password_hash($pswd, PASSWORD_DEFAULT);
  $pswd2 = password_hash($pswd2, PASSWORD_DEFAULT);
  $stmt = $db->prepare("INSERT INTO users (username,first_name,last_name,email,password,password2,) VALUES (:username,:first_name,:last_name,:email,:password,:password2,)");  
  $stmt->execute( array(':username'=>$un,':first_name'=>$fn,':last_name'=>$ln,':email'=>$em,':password'=>$pswd,':password2'=>$pswd2));
  }
  if ($stmt->rowCount() == 1) {
    header("Location: login.php");
  } 
  else {
    echo "error";
  }
}
?>

jquery码

$(document).ready(function(){
  $("form.register").change(function() {
    $.post("register.php", $("form.register").serialize(), function( data ) {
      if( data.flname == "cntbempty" )
        $("p#name_error").slideDown();
      else
        $("p#name_error").hide();
      if( data.username == "inuse" )
        $("p#username_error").slideDown();
      else
        $("p#username_error").hide();
      if( data.password == "missmatch" )
        $("p#password_error").slideDown();
      else
        $("p#password_error").hide();
      if( data.email == "notvalid" )
        $("p#email_error").slideDown();
      else
        $("p#email_error").hide();
    }, "json");
  });
});

Answer 1

你需要解决一些问题.

• 首先,处理注册过程的文件不应该与表单相同.
• 它纯粹用于处理数据,因此无法直接使用重定向浏览器header("Location: login.php").这部分应该由您的JavaScript代码处理.
• 您还需要告诉浏览器所提供的内容是JSON.
• 您还需要阻止表单直接提交

查看以下更新的代码.

创建一个名为:registrationHandler.php的文件

<?php
 if(isset($_POST['reg'])){
   $fn = ucfirst($_POST['fname']);
   $ln = ucfirst($_POST['lname']);
   $un = $_POST['username'];
   $em = $_POST['email'];
   $pswd = $_POST['password'];
   $pswd2 = $_POST['password2'];

   $sql=$db->prepare("SELECT username FROM users WHERE username=:username");
   $sql->execute(array(':username'=>$un));
   $row = $sql->fetch(PDO::FETCH_ASSOC);
   $db_username = $row['username'];
   $usernames = $db_username;

   $data = array();
   if( isset($fn) && isset($ln) ) {
    if( $fn != "" && $ln!="" && $fn == $ln ) {
      $data["flname"] = "cntbempty";
    }
  }
  if( isset($un) ) {
    if $un == $usernames )  {
  $data["username"] = "inuse";
}
}
if( isset($pswd) && isset($pswd2) ) {
  if( $pswd2 != "" && $pswd != $pswd2 ) {
    $data["password"] = "missmatch";
  }
}
if( isset( $em ) ) {
 if( $em != "" && !preg_match( "/^([a-zA-Z0-9])+([a-zA-Z0-9\._-])*@([a-zA-Z0-9_-])+([a-zA-Z0-9\._-]+)+$/", $_POST["email"] ) ) {
   $data["email"] = "notvalid";
 }
}
if(!empty($data))
{
  header('Content-Type: application/json');
  echo json_encode($data);
  die;
}
else{

  $pswd = password_hash($pswd, PASSWORD_DEFAULT);
  $pswd2 = password_hash($pswd2, PASSWORD_DEFAULT);
  $stmt = $db->prepare("INSERT INTO users (username,first_name,last_name,email,password,password2,) VALUES (:username,:first_name,:last_name,:email,:password,:password2,)");  
  $stmt->execute( array(':username'=>$un,':first_name'=>$fn,':last_name'=>$ln,':email'=>$em,':password'=>$pswd,':password2'=>$pswd2));
}
//! Send Success Status to browser for it to understand
if ($stmt->rowCount() == 1) {
  $data['success'] = true;
} 
else {
  $data['success'] = false;
}
header('Content-Type: application/json');
echo json_encode($data);
}
?>

你的Javascript代码:

$(document).ready(function(){
      $("form.register").submit(function(e) {
        e.preventDefault();
        $.post("registrationHandler.php", $("form.register").serialize(), function( data ) {
          if( data.flname == "cntbempty" )
            $("p#name_error").slideDown();
          else
            $("p#name_error").hide();
          if( data.username == "inuse" )
            $("p#username_error").slideDown();
          else
            $("p#username_error").hide();
          if( data.password == "missmatch" )
            $("p#password_error").slideDown();
          else
            $("p#password_error").hide();
          if( data.email == "notvalid" )
            $("p#email_error").slideDown();
          else
            $("p#email_error").hide();

          if(data.success) {
            // registration succesful. Redirect
            window.location = "login.php";
          }
          else {
            // Some database error?
          }
        }, "json");
      });
    });

Answer 2

正如@Novocaine所提到的,你在这里的问题是你在填写$data错误后让脚本继续.

对我来说,简单的做法是将你的$dataas作为一个空数组,然后只有在确实有错误的情况下填充它.

//changing the init of the $data array
$data = array();
if( isset($fn) && isset($ln) ) {
 if( $fn != "" && $ln!="" && $fn == $ln ) {
   $data["flname"] = "cntbempty";
  }
}
/* List of all your validation tests */

//Now your test if you have any errors in your $data
if(!empty($data))
{
    echo json_encode($data);
    die;
}

//And only after if the condition is not met, you can insert and redirect
/* Rest of your code here */

您还需要为jQuery代码添加一个条件以检查是否 data.flname定义了其他字段.

//example
if( data.flname && data.flname == "cntbempty" )
    $("p#name_error").slideDown();

我希望这有帮助.

Answer 3

header('Content-Type: application/json');之前添加echo json_encode($data);

$(document).ready(function(){
  $("form.register").submit(function(e) {
    e.preventDefault();
    $.post("register.php", $("form.register").serialize(), function( data ) {
      if(data.length == 0){
        window.location.href= "login.php";
      }

      if( data.flname == "cntbempty" )
        $("p#name_error").slideDown();
      else
        $("p#name_error").hide();
      if( data.username == "inuse" )
        $("p#username_error").slideDown();
      else
        $("p#username_error").hide();
      if( data.password == "missmatch" )
        $("p#password_error").slideDown();
      else
        $("p#password_error").hide();
      if( data.email == "notvalid" )
        $("p#email_error").slideDown();
      else
        $("p#email_error").hide();
    }, "json");
  });
});

替换header("Location: login.php");为echo(json_encode(array()))