如何使通知意图恢复而不是制定新的意图？

Question

我在这里有一个简单的webview活动,加载后它会自动显示正在进行的通知.我们的想法是,人们可以远离此活动,并通过下拉菜单并选择它,从他们想要的任何屏幕再次快速访问它.然后,当他们想要时,他们可以通过点击菜单按钮并点击退出来关闭通知,然后清除通知.一切正常.但是,当按下通知时,它会启动活动的新实例.我需要更改什么才能看到活动是否尚未被销毁,我可以回调用该实例(恢复它),因此不需要再次加载它,也不需要在我的堆栈中添加其他活动.有任何想法吗？任何帮助将不胜感激.

package com.my.app;

import com.flurry.android.FlurryAgent;

import android.app.Activity;
import android.app.Notification;
import android.app.NotificationManager;
import android.app.PendingIntent;
import android.app.ProgressDialog;
import android.content.Context;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.KeyEvent; 
import android.view.Menu;
import android.view.MenuInflater;
import android.view.MenuItem;
import android.webkit.CookieSyncManager;
import android.webkit.WebView;
import android.webkit.WebViewClient;
import android.widget.Toast;

public class Chat extends Activity { 
    private ProgressDialog progressBar;
    public WebView webview;
    private static final String TAG = "Main";

    private NotificationManager mNotificationManager;
    private int SIMPLE_NOTFICATION_ID;

    @Override
    public void onStart() {
       super.onStart();
       CookieSyncManager.getInstance().sync();
       FlurryAgent.onStartSession(this, "H9QGMRC46IPXB43GYWU1");
    }

    public void onCreate(Bundle savedInstanceState) { 
        super.onCreate(savedInstanceState);
        setContentView(R.layout.chat);

        mNotificationManager = (NotificationManager)getSystemService(NOTIFICATION_SERVICE);

        final Notification notifyDetails = new Notification(R.drawable.chat_notification,"Chat Started",System.currentTimeMillis());

        notifyDetails.flags |= Notification.FLAG_ONGOING_EVENT;

        Context context = getApplicationContext();

        CharSequence contentTitle = "Chat";
        CharSequence contentText = "Press to return to chat";

        Intent notifyIntent = new Intent(context, Chat.class);

        PendingIntent intent =
        PendingIntent.getActivity(Chat.this, 0,
        notifyIntent, android.content.Intent.FLAG_ACTIVITY_NEW_TASK);
        notifyDetails.setLatestEventInfo(context, contentTitle, contentText, intent);

        mNotificationManager.notify(SIMPLE_NOTFICATION_ID, notifyDetails);

        CookieSyncManager.createInstance(this);
        CookieSyncManager.getInstance().startSync();
        webview = (WebView) findViewById(R.id.webviewchat);
        webview.setWebViewClient(new chatClient());
        webview.getSettings().setJavaScriptEnabled(true);
        webview.getSettings().setPluginsEnabled(true);
        webview.loadUrl("http://google.com");

        progressBar = ProgressDialog.show(Chat.this, "", "Loading Chat...");  
    }

    private class chatClient extends WebViewClient { 
        @Override 
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            Log.i(TAG, "Processing webview url click...");
            view.loadUrl(url);
            return true;
        }

        public void onPageFinished(WebView view, String url) {
            Log.i(TAG, "Finished loading URL: " +url);
            if (progressBar.isShowing()) {
                progressBar.dismiss();
            }
        }
    }

    public boolean onKeyDown(int keyCode, KeyEvent event) { 
        if ((keyCode == KeyEvent.KEYCODE_BACK) && webview.canGoBack()) { 
            webview.goBack(); 
            return true; 
        }
        return super.onKeyDown(keyCode, event); 
    }

    @Override
    public boolean onCreateOptionsMenu (Menu menu) {
        super.onCreateOptionsMenu(menu);
        MenuInflater inflater = getMenuInflater();
        inflater.inflate(R.menu.chatmenu, menu);
        return true;
    }

    @Override
    public boolean onOptionsItemSelected (MenuItem item) {
        switch (item.getItemId()) {
            case R.id.home:
                Intent a = new Intent(this, Home.class);
                startActivity(a);
                return true;
            case R.id.closechat:
                mNotificationManager.cancel(SIMPLE_NOTFICATION_ID);
                Intent v = new Intent(this, Home.class);
                startActivity(v);
                return true;
        }
        return false;
    }

    public void onStop() {
       super.onStop();
       CookieSyncManager.getInstance().sync();
       FlurryAgent.onEndSession(this);
    }
}

@Commonsware

只是为了确保我说得对,这是你的建议吗？

我有点担心这条线,

PendingIntent.getActivity(Chat.this, 0, notifyIntent, SIMPLE_NOTFICATION_ID);

public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState);
    setContentView(R.layout.chat);

    mNotificationManager = (NotificationManager)getSystemService(NOTIFICATION_SERVICE);

    final Notification notifyDetails = new Notification(R.drawable.chat_notification,"Chat Started",System.currentTimeMillis());

    notifyDetails.flags |= Notification.FLAG_ONGOING_EVENT;


    Context context = getApplicationContext();

    CharSequence contentTitle = "Chat";
    CharSequence contentText = "Press to return to chat";

    Intent notifyIntent = new Intent(context, Chat.class);

    PendingIntent intent =
    PendingIntent.getActivity(Chat.this, 0, notifyIntent, SIMPLE_NOTFICATION_ID);
    notifyDetails.setLatestEventInfo(context, contentTitle, contentText, intent);
    notifyIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);

    mNotificationManager.notify(SIMPLE_NOTFICATION_ID, notifyDetails);


    CookieSyncManager.createInstance(this);
    CookieSyncManager.getInstance().startSync();
    webview = (WebView) findViewById(R.id.webviewchat);
    webview.setWebViewClient(new chatClient());
    webview.getSettings().setJavaScriptEnabled(true);
    webview.getSettings().setPluginsEnabled(true);
    webview.loadUrl("http://google.com");

    progressBar = ProgressDialog.show(Chat.this, "", "Loading Chat...");        
}

Answer 1

我们的想法是,人们可以远离此活动,并通过下拉菜单并选择它,从他们想要的任何屏幕再次快速访问它.

请选择此选项.

但是,当按下通知时,它会启动活动的新实例.

这将默认发生.

我需要更改什么才能看到活动是否尚未被销毁,我可以回调用该实例(恢复它),因此不需要再次加载它,也不需要在我的堆栈中添加其他活动.

摆脱FLAG_ACTIVITY_NEW_TASK.添加notifyIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);- 请参阅此示例项目.

Context context = getApplicationContext();

请不要这样做.只需使用你Activity的Context.

Answer 2

这是我显示通知的方法.我希望它对你有所帮助.

private static void generateNotification(Context context, String message){
    Intent notificationIntent = new Intent(context, YOUR_ACTIVITY.class);
    notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);
    PendingIntent intent = PendingIntent.getActivity(context, 0, notificationIntent, 0);

    NotificationCompat.Builder mBuilder = new NotificationCompat.Builder(context)
        .setSmallIcon(R.drawable.ic_launcher)
        .setContentTitle(context.getString(R.string.app_name))
        .setContentIntent(intent)
        .setPriority(PRIORITY_HIGH) //private static final PRIORITY_HIGH = 5;
        .setContentText(message)
        .setAutoCancel(true)
        .setDefaults(Notification.DEFAULT_SOUND | Notification.DEFAULT_VIBRATE | Notification.DEFAULT_LIGHTS);
    NotificationManager mNotificationManager = (NotificationManager) context.getSystemService(Context.NOTIFICATION_SERVICE);
    mNotificationManager.notify(0, mBuilder.build());
}

Answer 3

以防其他人遇到同样的困难....

我尝试了上面的所有代码但没有成功 - 通知项目继续启动我的应用程序的全新实例,即使其中一个已经运行.(我只想在任何时候有一个实例可用.)最后注意到另一个线程(/sf/answers/1450693961/),它在清单中需要一个简单的附加条目:

android:launchMode="singleInstance"

我将它放在我的应用程序的主要活动部分下的清单中,然后通知项重用已经在进行中的实例.