Sar*_*ran 5 html css twitter-bootstrap
如何在单击下拉菜单时上下改变引导下拉箭头.这有可能使用CSS吗?
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
<link href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css" rel="stylesheet"/>
<li class="dropdown">
<a href="#" style="text-decoration:none" class="dropdown-toggle" data-toggle="dropdown">Dropdown <span class="caret"></span></a>
<ul class="dropdown-menu">
<li><a href="#">Menu1</a></li>
<li><a href="#">Menu2</a></li>
<li><a href="#">Menu3</a></li>
</ul>
</li>Run Code Online (Sandbox Code Playgroud)
在下面添加代码底部的css样式.并让我知道它是否有效.
.dropdown.open .caret {
display: inline-block;
width: 0;
height: 0;
margin-left: 2px;
vertical-align: middle;
border-bottom: 4px dashed;
border-top: 0px solid transparent;
border-right: 4px solid transparent;
border-left: 4px solid transparent;
}
Run Code Online (Sandbox Code Playgroud)
添加这个CSS:
li.open > a > span{
border-top: 0px !important;
border-bottom: 4px dashed !important;
}
Run Code Online (Sandbox Code Playgroud)
当列表打开时,它将选择您的跨度(基本上是向上或向下的箭头)。当它包含 class 时.open。然后它将更改 spans css 定义并转动箭头。
输出:
li.open > a > span{
border-top: 0px !important;
border-bottom: 4px dashed !important;
}
Run Code Online (Sandbox Code Playgroud)
li.open > a > span {
border-top: 0px !important;
border-bottom: 4px dashed !important;
}Run Code Online (Sandbox Code Playgroud)