der*_*khh 4 c# task-parallel-library async-await
我发现以下代码实际上不会等待任务client.SendAsync()如果我使用实现:
taskList.Add(Task.Factory.StartNew(() => new Program().Foo()));
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如果我将其更改Task.Factory.StartNew()为just new Program().Foo()或者Task.Run(() => new Program.Foo()它将正确输出一些信息.两者有什么不同?
internal class Program
{
private async Task Foo()
{
while (true)
{
var client = new HttpClient();
var requestMessage = new HttpRequestMessage(HttpMethod.Head, "http://www.google.com");
HttpResponseMessage response = await client.SendAsync(requestMessage);
Console.WriteLine(response.RequestMessage.RequestUri.ToString());
}
}
private static void Main(string[] args)
{
var taskList = new List<Task>();
// This won't output anything.
taskList.Add(Task.Factory.StartNew(() => new Program().Foo()));
// This will.
taskList.Add(Task.Run(() => new Program().Foo()));
// So does this.
taskList.Add(new Program().Foo());
Task.WaitAll(taskList.ToArray());
}
}
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基于这篇MSDN文章,它似乎Task.Run(someAction);相当于Task.Factory.StartNew(someAction, CancellationToken.None, TaskCreationOptions.DenyChildAttach, TaskScheduler.Default);
但即使我将代码更改为此代码,它也不会输出任何内容.为什么?
internal class Program
{
private async Task Foo()
{
while (true)
{
var client = new HttpClient();
var requestMessage = new HttpRequestMessage(HttpMethod.Head, "http://www.google.com");
HttpResponseMessage response = await client.SendAsync(requestMessage);
Console.WriteLine(response.RequestMessage.RequestUri.ToString());
}
}
private static void Main(string[] args)
{
var taskList = new List<Task>();
taskList.Add(Task.Factory.StartNew(() => new Program().Foo(), CancellationToken.None,
TaskCreationOptions.DenyChildAttach, TaskScheduler.Default));
//taskList.Add(Task.Run(() => new Program().Foo()));
//taskList.Add(new Program().Foo());
Task.WaitAll(taskList.ToArray());
}
}
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Yuv*_*kov 13
问题在于Task.Factory.StartNew不是"任务感知" 的事实.意思是,方法调用的返回类型StartNew实际上是一个Task<Task>.这意味着你只是在等待外部任务完成,而不是内部任务.
一个简单的解决方案是使用该TaskExtensions.Unwrap()方法:
private static void Main(string[] args)
{
var taskList = new List<Task>();
taskList.Add(Task.Factory.StartNew(() => new Program().Foo()).Unwrap());
Task.WaitAll(taskList.ToArray());
}
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Task.Run确实有效,因为它是"任务感知".它有一个重载Func<Task>,它在内部调用Unwrap你,只返回内部任务.
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