问题使用Spring MVC中的JAXB注释对Jackson进行反序列化

Question

我在调用服务时让杰克逊正确地将json反序列化为一个对象(特别是我们使用Jackson的能力来使用JAXB注释,因为我们也希望服务使用XML).我正在使用Spring MVC,我正在使用RestTemplate类来调用服务.

这是我为junit设置MappingJacksonHttpMessageConverter的地方:

ObjectMapper jsonMapper = new ObjectMapper();
AnnotationIntrospector introspector = new JaxbAnnotationIntrospector();
jsonMapper.getDeserializationConfig().setAnnotationIntrospector(introspector);
jsonMapper.getSerializationConfig().setAnnotationIntrospector(introspector);
jsonMapper.getSerializationConfig().setSerializationInclusion(Inclusion.NON_NULL);
MappingJacksonHttpMessageConverter jacksonConverter = new MappingJacksonHttpMessageConverter();
jacksonConverter.setObjectMapper(jsonMapper);
List<HttpMessageConverter<?>> converters = new ArrayList<HttpMessageConverter<?>>();
converters.add(jacksonConverter);
template.setMessageConverters(converters);

我这样称呼服务:

HttpHeaders requestHeaders = new HttpHeaders();
requestHeaders.set("Accept", "application/json");
HttpEntity<String> requestEntity = new HttpEntity<String>(requestHeaders);
ResponseEntity<NamedSystem> responseEntity = template.exchange(baseURL + "/{NamedSystemId}", 
        HttpMethod.GET, requestEntity, NamedSystem.class, orgId1);

我的NamedSystem课程设置如下:

@XmlRootElement(name = "NamedSystem", namespace = "http://schemas.abc.workplace.com/NamedSystem")
public class NamedSystem {
    private String id;
    private String name;
    private String description;
    private Set<NamedSystemAlias> aliases;
    private String href;

    @XmlAttribute(required = false, name = "id")
    public String getId() {
        return id;
    }


    public void setId(String id) {
        this.id = id;
    }


    @XmlAttribute(required = false, name = "name")
    public String getName() {
        return name;
    }


    public void setName(String name) {
        this.name = name;
    }


    @XmlAttribute(required = false, name = "description")
    public String getDescription() {
        return description;
    }


    public void setDescription(String description) {
        this.description = description;
    }


    @XmlElementWrapper(required = false, name = "aliases", namespace = "http://schemas.abc.workplace.com/NamedSystem")
    @XmlElement(required = false, name = "alias", namespace = "http://schemas.abc.workplace.com/NamedSystem")
    public Set<NamedSystemAlias> getAliases() {
        return aliases;
    }


    public void setAliases(Set<NamedSystemAlias> aliases) {
        this.aliases = aliases;
    }

    @XmlAttribute(required = true, name = "href")
    public String getHref() {
        return href;
    }


    public void setHref(String href) {
        this.href = href;
    }
}

这是导致的错误:

org.springframework.web.client.ResourceAccessException: I/O error: Unrecognized field "NamedSystem" (Class com.workplace.abc.named.NamedSystem), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@c1429c; line: 1, column: 2]; nested exception is org.codehaus.jackson.map.JsonMappingException: Unrecognized field "NamedSystem" (Class com.workplace.abc.named.NamedSystem), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@c1429c; line: 1, column: 2]
 at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:453)
....
Caused by: org.codehaus.jackson.map.JsonMappingException: Unrecognized field "NamedSystem" (Class com.workplace.abc.named.NamedSystem), not marked as ignorable
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@c1429c; line: 1, column: 2]
 at org.codehaus.jackson.map.JsonMappingException.from(JsonMappingException.java:159)
 at org.codehaus.jackson.map.deser.StdDeserializationContext.unknownFieldException(StdDeserializationContext.java:247)
 at org.codehaus.jackson.map.deser.StdDeserializer.reportUnknownProperty(StdDeserializer.java:366)
 at org.codehaus.jackson.map.deser.StdDeserializer.handleUnknownProperty(StdDeserializer.java:352)
 at org.codehaus.jackson.map.deser.BeanDeserializer.handleUnknownProperty(BeanDeserializer.java:543)
 at org.codehaus.jackson.map.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:402)
 at org.codehaus.jackson.map.deser.BeanDeserializer.deserialize(BeanDeserializer.java:287)
 at org.codehaus.jackson.map.ObjectMapper._readMapAndClose(ObjectMapper.java:1588)
 at org.codehaus.jackson.map.ObjectMapper.readValue(ObjectMapper.java:1172)
 at org.springframework.http.converter.json.MappingJacksonHttpMessageConverter.readInternal(MappingJacksonHttpMessageConverter.java:132)
 at org.springframework.http.converter.AbstractHttpMessageConverter.read(AbstractHttpMessageConverter.java:154)
 at org.springframework.web.client.HttpMessageConverterExtractor.extractData(HttpMessageConverterExtractor.java:74)
 at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:619)
 at org.springframework.web.client.RestTemplate$ResponseEntityResponseExtractor.extractData(RestTemplate.java:1)
 at org.springframework.web.client.RestTemplate.doExecute(RestTemplate.java:446)
 ... 32 more

它似乎无法识别rootElement'NamedSystem'能够反序列化.我怎么能这样做呢？我见过使用相同JAXB注释的示例,它们工作正常,所以我不确定我的情况有什么不同,或者我怎么强迫它正确地反序列化它.如果有人可以提供任何帮助,我会很感激.

Answer 1

如果有人遇到此类问题，这可能会为您解决：Enable Jackson to not output the class name when serializing (using Spring MVC)

请参阅我的答案并点击链接查看示例。