dateTime到Epoch,反之亦然xslt

Question

我一直在尝试将给定的dateTime转换为纪元时间,并将给定的纪元时间转换为dateTime.我对xslt很新,并且已经在这方面苦苦挣扎了一段时间,它没有给我任何结果.到目前为止,这是我的xslt

    <xsl:stylesheet version="1.0"
                xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
                xmlns:ns0="http://www.NoPreAuth.org"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                exclude-result-prefixes="xsi xsl ns0 xsd">
<xsl:template match="/">
<xsl:variable name="date1">
        <xsl:value-of select="/ns0:NoAuthInput/ns0:StartDate"/>
</xsl:variable>
<xsl:variable name="date2">
        <xsl:value-of select="/ns0:NoAuthInput/ns0:EndDate"/>
</xsl:variable>
<ns0:NoPreAuthInput>
<ns0:Product>
        <xsl:value-of select="/ns0:NoAuthInput/ns0:Product"/>
</ns0:Product>
<!-- datTime to epoch -->
<ns0:END_T> 
  <xsl:value-of select= "(('$date1')  - xsd:dateTime('1970-01-01T00:00:00') )  div  xsd:dayTimeDuration('PT1S') "/>
</ns0:END_T>
<!-- epoch To datTime -->
<ns0:Closed_T> 
  <xsl:value-of select= "(('$date2')  + xsd:dateTime('1970-01-01T00:00:00') )  *  xsd:dayTimeDuration('PT1S') "/>
</ns0:Closed_T>
</ns0:NoPreAuthInput>
</xsl:template>
</xsl:stylesheet>

我想要转换的xml是:

<?xml version="1.0" encoding="UTF-8" ?>
<NoAuthInput xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.NoAuth.org 

 xmlns="http://www.NoAuth.org">
   <Product>ABC</Product>
   <StartDate>2015-10-05T15:52:40.782</StartDate>
   <EndDate>1444150760</EndDate>
</NoAuthInput> 

任何帮助都非常感谢.谢谢

Answer 1

To convert Unix time to ISO 8601 date-time:

<xsl:value-of select="xs:dateTime('1970-01-01T00:00:00') + xs:dayTimeDuration(concat('PT', UnixTime, 'S'))"/>

将ISO 8601日期时间转换为Unix时间;

<xsl:value-of select="floor((xs:dateTime(ISODateTime) - xs:dateTime('1970-01-01T00:00:00')) div xs:dayTimeDuration('PT1S')) "/>

需要XSLT 2.0.

工作演示:http://xsltransform.net/94rmq5L