MySQL查询10表(Sequelize或Raw Query)

Question

为了返回以下JSON示例,我们需要查询10个表,同时查找其间的值.我对SQL的了解有限,所以我们在这里寻求帮助.

JSON:

{
  project: 1,
  name: "BluePrint1",
  description: "BluePrint 1 Description",
  listWorkPackages: [
    {
      id: 1,
      name: "WorkPackage 1 Name",
      description: "WorkPackage 1 Description",
      type: "WorkPackage Type",
      department: "WorkPackage Department",
      status: "Workpackage work status"
    },
    {
      id: 2,
      name: "WorkPackage 2 Name",
      description: "WorkPackage 2 Description",
      type: "WorkPackage Type",
      department: "WorkPackage Department",
      status: "Workpackage work status"
    }
  ],
  assignments: [
    {
      id: 3,
      name: "WorkPackage 3 Name",
      description: "WorkPackage 3 Description",
      type: "WorkPackage Type",
      department: "WorkPackage Department",
      status: "Workpackage work status"
    }
  ]
}

数据库:

数据库看起来像这样(在新标签中打开以获取更多详细信息):

逻辑:

使用WorkerID,我们希望所有WorkPackages:

• 与工人有相同的类型 ;
• 并属于同一部门 ;
• 还有直接分配的那些(通过表WA_Assignments)

所以我们可以发送JSON上的信息,我们需要查看这10个表:

1. WK_Worker
2. WT_WorkerType
3. TY_Type
4. WP_WorkPackage
5. WE_WorkPackageExecution
6. WS_WorkStatus
7. BL_Blueprint
8. PR_Project
9. DP_Department
10. WA_WorkAssignments

我的问题:

我对SQL的了解仅限于JOIN:

SELECT *
FROM BL_Blueprint 
JOIN PR_Project ON BL_idBlueprint = PR_idBlueprint
JOIN WP_WorkPackage ON BL_idBlueprint = WP_idBlueprint
JOIN WE_WorkPackageExecution ON WE_idWorkPackage = WP_idWorkPackage
JOIN DP_Department ON WE_idDepartment = DP_idDepartment

我们只需要搜索与Worker 类型相同的工作包,但只有在查看表WT_WorkerType之后我们才知道这些类型.

我读到了关于你可以在WHERE字段中选择SELECT的subQuery,但是无法理解它,并得到一个有效的查询.

问题:

最后,我的问题是:

1. SQL查询;

我正在使用Sequelize,如果它可以提供帮助,但是从文档中我认为Raw Query会更容易.

谢谢大家的帮助和支持.

---

解

所有的爱都归于@MihaiOvidiuDrăgoi(在评论中),帮助我找到了解决方案

第一个 SELECT获取赋值,第二个获取上面描述的逻辑.标签有助于确定哪个是哪个,我们为了简化JSON的创建而命令.

SELECT *
FROM
    ((SELECT 
        BL_Name,
            BL_Description,
            WP_Name,
            WP_Description,
            PR_idProject,
            WE_idWorkPackageExecution,
            WE_idWorkStatus,
            TY_TypeName,
            TY_Description,
            WS_WorkStatus,
            DP_Name,
            DP_Description,
            'second_select'
    FROM
        WK_Worker, WP_WorkPackage
    INNER JOIN BL_Blueprint ON BL_idBlueprint = WP_idBlueprint
    INNER JOIN PR_Project ON PR_idBlueprint = BL_idBlueprint
    INNER JOIN WE_WorkPackageExecution ON WE_idWorkPackage = WP_idWorkPackage
        AND WE_idProject = PR_idProject
    INNER JOIN WS_WorkStatus ON WS_idWorkStatus = WE_idWorkStatus
    INNER JOIN DP_Department ON DP_idDepartment = WE_idDepartment
    INNER JOIN WA_WorkAssignments ON WA_idWorkPackageExecution = WE_idWorkPackageExecution
    INNER JOIN TY_Type ON TY_idType = WP_idType
    WHERE
        WA_idWorker = 1 AND WK_idWorker = 1) UNION ALL (SELECT 
        BL_Name,
            BL_Description,
            WP_Name,
            WP_Description,
            PR_idProject,
            WE_idWorkPackageExecution,
            WE_idWorkStatus,
            TY_TypeName,
            TY_Description,
            WS_WorkStatus,
            DP_Name,
            DP_Description,
            'first_select'
    FROM
        WK_Worker, WP_WorkPackage
    JOIN BL_Blueprint ON BL_idBlueprint = WP_idBlueprint
    JOIN PR_Project ON PR_idBlueprint = BL_idBlueprint
    JOIN WE_WorkPackageExecution ON WE_idWorkPackage = WP_idWorkPackage
        AND WE_idProject = PR_idProject
    JOIN WS_WorkStatus ON WS_idWorkStatus = WE_idWorkStatus
    JOIN DP_Department ON DP_idDepartment = WE_idDepartment
    JOIN TY_Type ON TY_idType = WP_idType
    WHERE
        WK_idWorker = 1
            AND DP_idDepartment IN 
            (SELECT 
                WK_idDepartment
            FROM
                WK_Worker
            WHERE
                WK_idWorker = 1)
            AND WP_idType IN 
            (SELECT 
                TY_idType
            FROM
                TY_Type
            JOIN WT_WorkerType ON TY_idType = WT_idType
            WHERE
                WT_idWorker = 1)
    )
) AS T1
ORDER BY T1.PR_idProject

Answer 1

由于您似乎需要一个由两个不同连接组成的单个结果集，因此您可能应该执行类似的操作

SELECT * from
(
SELECT 1 
UNION ALL 
SELECT 2 
) a
ORDER by ...

您的两个 select 语句还应包含逻辑名称作为不同的列（如“firstselect”） - 这样您就知道您的行来自哪个选择。