如何在python中创建顺序组合列表?

Jos*_*eph 6 python python-itertools

我有一个列表['a','b','c','d']我需要一个列表['a','ab','abc','abcd','b',' bc','bcd','c','cd','d'].

我一直在看itertools,但我没有看到如何使这项工作.

对于所有组合,代码将是:

from itertools import permutations
stuff = ['a','b','c','d']
for i in range(0, len(stuff)+1):
    for subset in permutations(stuff, i):
           print(subset)
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如果只返回顺序组合,我需要做什么?我想我可以随时检查每个排列的顺序,但这似乎不是最好的方法.

njz*_*zk2 5

很简单:

stuff = ['a','b','c','d']
print([''.join(stuff[i:j]) for i in range(len(stuff)) for j in range(i+1, len(stuff)+1)])
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['a', 'ab', 'abc', 'abcd', 'b', 'bc', 'bcd', 'c', 'cd', 'd']
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