Swift 2:守卫for for循环?

lon*_*bow 16 error-handling for-loop ios swift2

在for循环中使用guard的正确方法是什么?

for (index,user) in myUsersArray.enumerate() {

    guard user.id != nil else {
        print("no userId")
        //neither break / return will keep running the for loop
    }

    if user.id == myUser.id {

        //do stuff

    }
}
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Ars*_*sen 25

有几种方法可以制定一些条件:

你可以为整个条件.每次迭代都会调用它

for (index, user) in myUsersArray.enumerate() where check() {}
for (index, user) in myUsersArray.enumerate() where flag == true {}
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您可以检查内部的内容并跳过迭代或停止循环:

for (index, user) in myUsersArray.enumerate() {
    guard check() else { continue }
    guard flag else { break }
}
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在你的情况下,我会写这样的东西:

for (index, user) in myUsersArray.enumerate() {
    guard let userId = user.id, userId == myUser.id else { continue }

    // do stuff with userId
}
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Lev*_*dau 5

@Arsens的答案是正确的,但我认为这更容易理解

let ints = [1,2,3,4,5]

for (index,value) in ints.enumerate() {

        guard value != 1 else {
            print("Guarded \(value)")
            continue
        }

        print("Processed \(value)")
}
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