如何限制UITextView中的行数?

Raw*_*wan 10 uitextview ios swift

我的屏幕上有一个UITextView,用户应该只填充两行,当用户在第二行时,返回键应该变为Done.

如何限制UITextView中的数?我搜索了很多,没有结果有用!

我找到了Swift的答案:

locationNoteTextView.textContainer.maximumNumberOfLines = 2
self.locationNoteTextView.textContainer.lineBreakMode = NSLineBreakMode.ByClipping
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它不起作用,通过这种方式用户可以输入无限字符,但在屏幕上查看的只是两行!

因此,如果您尝试打印textView文本,您将找到灾难文本.

Abh*_*nav 17

你需要实施textView:shouldChangeTextInRange:replacementText:.只要文本要更改,就会调用此方法.您可以使用其text属性访问文本视图的当前内容.

使用传递的范围和替换文本构造新内容[textView.text stringByReplacingCharactersInRange:range withString:replacementText].

然后,您可以计算行数并返回YES以允许更改或NO拒绝它.

编辑:在OP请求:

func sizeOfString (string: String, constrainedToWidth width: Double, font: UIFont) -> CGSize {
    return (string as NSString).boundingRectWithSize(CGSize(width: width, height: DBL_MAX),
        options: NSStringDrawingOptions.UsesLineFragmentOrigin,
        attributes: [NSFontAttributeName: font],
        context: nil).size
}


func textView(textView: UITextView, shouldChangeTextInRange range: NSRange, replacementText text: String) -> Bool {
    let newText = (textView.text as NSString).stringByReplacingCharactersInRange(range, withString: text)
    var textWidth = CGRectGetWidth(UIEdgeInsetsInsetRect(textView.frame, textView.textContainerInset))
    textWidth -= 2.0 * textView.textContainer.lineFragmentPadding;

    let boundingRect = sizeOfString(newText, constrainedToWidth: Double(textWidth), font: textView.font!)
    let numberOfLines = boundingRect.height / textView.font!.lineHeight;

    return numberOfLines <= 2;
}
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Rah*_*ule 13

适用于iOS 7+

textView.textContainer.maximumNumberOfLines = 10;
textView.textContainer.lineBreakMode = NSLineBreakByTruncatingTail;
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要么

textView.textContainer.maximumNumberOfLines = 10;
[textView.layoutManager textContainerChangedGeometry:textView.textContainer];
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