从文本文件中读取JSON

tes*_*est 8 java json

我知道一些JSON库,我现在正在研究Google-JSON,但我想要实现的只是简单的事情,我想知道你会建议什么.

我想要一个JSON库,让我读取一个JSON文本文件,让我把它转换成字符串,int,boolean等. - 现在使用Json.org/java

它可以阅读!但!!

import org.json.*;

public class readJ {

    public static String MapTitle;
    public static int[][] tiles;

    public static void main(String[] args) {

                       String json =
               "{"
               +"'name': 'map_one.txt',"
                +"'title': 'Map One',"
                +"'currentMap': 4,"
                +"'items': ["
                     +"{ name: 'Pickaxe', x: 5, y: 1 },"
                     +"{ name: 'Battleaxe', x: 2, y: 3 }"
                     +"],"
                +"map': [ [ 1,3,1,1,1,24,1,1,1,1,1,1,1 ],"
                    +"[ 1,3,1,1,1,24,1,1,1,1,1,1,1 ],"
                    +"[ 1,7,1,1,1,24,1,1,24,1,1,1,1 ],"
                    +"[ 1,7,1,1,7,1,1,1,24,1,1,1,1 ],"
                    +"[ 1,7,7,7,1,24,24,24,24,1,1,1,1 ],"
                    +"[ 1,1,7,1,1,24,1,24,1,1,1,1,1 ],"
                    +"[ 1,1,1,1,1,24,1,1,1,1,1,1,1 ],"
                    +"[ 1,1,3,1,1,24,1,1,1,1,1,1,1 ],"
                    +"[ 1,3,3,1,1,24,1,1,1,1,1,1,1 ]]"
+"}";
try {
JSONObject JsonObj = new JSONObject(json);
MapTitle = JsonObj.getString("title");
tiles = JsonObj.getJSONArray("map");
}catch (JSONException er) {
    er.printStackTrace();
}

System.out.println(MapTitle);
System.out.println(tiles[0][1]);

    }
}
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编译时我收到此错误:

C:\Users\Dan\Documents\readJSON\readJ.java:32: incompatible types
found   : org.json.JSONArray
required: int[][]
tiles = JsonObj.getJSONArray("map");
                            ^
1 error

Tool completed with exit code 1
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Bal*_*usC 4

安装Google Gson并创建这两个模型类

public class Data {
    private String name;
    private String title;
    private int currentMap;
    private List<Item> items;
    private int[][] map;

    public String getName() { return name; }
    public String getTitle() { return title; }
    public int getCurrentMap() { return currentMap; }
    public List<Item> getItems() { return items; }
    public int[][] getMap() { return map; }

    public void setName(String name) { this.name = name; }
    public void setTitle(String title) { this.title = title; }
    public void setCurrentMap(int currentMap) { this.currentMap = currentMap; }
    public void setItems(List<Item> items) { this.items = items; }
    public void setMap(int[][] map) { this.map = map; }
}
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public class Item {
    private String name;
    private int x;
    private int y;

    public String getName() { return name; }
    public int getX() { return x; }
    public int getY() { return y; }

    public void setName(String name) { this.name = name; }
    public void setX(int x) { this.x = x; }
    public void setY(int y) { this.y = y; }
}
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并按如下方式转换 JSON:

Data data = new Gson().fromJson(json, Data.class);
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要获得标题,只需执行以下操作:

System.out.println(data.getTitle()); // Map One
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并获取 x=3 和 y=3 处的地图项:

System.out.println(data.getMap()[3][3]); // 1
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并获取第一个的名称Item

System.out.println(data.getItems().get(0).getName()); // Pickaxe
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简单的!使用其他方式转换也很简单Gson#toJson()

String json = new Gson().toJson(data);
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另请参阅此答案以了解另一个复杂的 Gson 示例。