JDe*_*off 6 java httpurlconnection
嘿,我正试图从推特个人资料页面获取html,但httpurlconnection只返回一小段html.我的代码
for(int i = 0; i < urls.size(); i++)
{
URL url = new URL(urls.get(i));
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestProperty("User-Agent","Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.6) Gecko/20100625 Firefox/3.6.6");
System.out.println(connection.getResponseCode());
String line;
StringBuilder builder = new StringBuilder();
BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
while((line = reader.readLine()) != null)
{
builder.append(line);
}
String html = builder.toString();
}
Run Code Online (Sandbox Code Playgroud)
我总是得到200作为每次通话的响应代码.然而,大约1/3的时间返回整个html文档,而另一半只返回前几百行.html被截止时返回的数量并不总是相同的.
有任何想法吗?谢谢你的帮助!
附加信息:查看标题后,我似乎得到重复的内容长度标题.第一个是全长,另一个是更短(并且可能代表我在某些时候得到的长度)如何处理重复的标题?
这对我来说效果很好,我在后面添加了一个换行符builder.append(line);以使其在控制台中更具可读性,但除此之外它返回了该页面的所有 HTML:
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.ArrayList;
import java.util.List;
public class RetrieveHTML {
public static void main(String[] args) throws IOException {
List<String> urls = new ArrayList<String>();
urls.add("http://stackoverflow.com/questions/3285077/java-httpurlconnection-cutting-off-html");
for (int i = 0; i < urls.size(); i++) {
URL url = new URL(urls.get(i));
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
connection.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows; U; Windows NT 6.1; en-US; rv:1.9.2.6) Gecko/20100625 Firefox/3.6.6");
System.out.println(connection.getResponseCode());
String line;
StringBuilder builder = new StringBuilder();
BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
while ((line = reader.readLine()) != null) {
builder.append(line);
builder.append("\n");
}
String html = builder.toString();
System.out.println("HTML " + html);
}
}
}
Run Code Online (Sandbox Code Playgroud)