Jel*_*eij 5 mongodb mongodb-query aggregation-framework
在我的申请中,我有以下文件
{
"timestamp": ISODate("2015-09-17T21:14:35.0Z"),
"sensor": "gas-in",
"value": 2.5,
},
{
"timestamp": ISODate("2015-09-17T21:14:35.0Z"),
"sensor": "gas-out",
"value": 2.0,
},
{
"timestamp": ISODate("2015-09-17T21:20:35.0Z"),
"sensor": "gas-in",
"value": 6.3,
},
{
"timestamp": ISODate("2015-09-17T21:20:35.0Z"),
"sensor": "gas-out",
"value": 0.8,
}
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...等等...
如何返回按时间戳分组的差异 (gas-in) - (gas-out) ?我正在尝试编写一个像这样返回它的函数:
{
"timestamp": ISODate("2015-09-17T21:14:35.0Z"),
"sensor": "gas-difference",
"value": 0.5, // is calculated by 2.5 - 2.0
},
{
"timestamp": ISODate("2015-09-17T21:20:35.0Z"),
"sensor": "gas-difference",
"value": 5.5, // is calculated by 6.3 - 0.8
},
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...等等...
我玩过聚合函数和 $subtract,阅读其他 SO 问题,但他们似乎没有回答我的问题。在其他问题中,他们似乎知道要从彼此中减去哪个 2 个文档,但在我的情况下,我不知道文档的数量,并且 $timestamp “列”是两个文档的匹配标识符。
有人可以帮我解决这个问题吗?谢谢!
您首先需要的是$sum
基于$cond
每个值分组中的运算符的条件。然后你可以分别$subtract
:
db.gas.aggregate([
{ "$group": {
"_id": "$timestamp",
"gas-in": {
"$sum": {
"$cond": [
{ "$eq": [ "$sensor", "gas-in" ] },
"$value",
0
]
}
},
"gas-out": {
"$sum": {
"$cond": [
{ "$eq": [ "$sensor", "gas-out"] },
"$value",
0
]
}
},
}},
{ "$project": {
"gasdifference": { "$subtract": [ "$gas-in", "$gas-out" ] }
}}
])
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这给出了结果:
{ "_id" : ISODate("2015-09-17T21:20:35Z"), "gasdifference" : 5.5 }
{ "_id" : ISODate("2015-09-17T21:14:35Z"), "gasdifference" : 0.5 }
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另一种方法是使单个阶段的“gas-out”值为负:
db.gas.aggregate([
{ "$group": {
"_id": "$timestamp",
"gasdifference": {
"$sum": {
"$cond": [
{ "$eq": [ "$sensor", "gas-in" ] },
"$value",
{ "$subtract": [ 0, "$value" ] }
]
}
}
}}
])
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这会更有效率。
如果您有两个以上可能的“传感器”值,那么您只需“嵌套”以下$cond
语句:
db.gas.aggregate([
{ "$group": {
"_id": "$timestamp",
"gasdifference": {
"$sum": {
"$cond": [
{ "$eq": [ "$sensor", "gas-in" ] },
"$value",
{ "$cond": [
{ "$eq": [ "$sensor", "gas-out" ] },
{ "$subtract": [ 0, "$value" ] },
0
]}
]
}
}
}}
])
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由于它们是“三元”运算符( if-then-else ),因此任何进一步的逻辑都属于“else”条件。