在iOS 9中不推荐使用sendAsynchronousRequest

Question

我正在尝试将我的代码从Swift 1.2更改为Swift 2.0,但我遇到了一些关于"sendAsynchronousRequest"的问题,因为它总是显示警告,因为它已被弃用.我尝试过使用此帖子中的其他解决方案:不能在Swift 2中使用参数列表调用'sendAsynchronousRequest'但它仍然无法工作,我再次收到相同的警告.

我必须在代码中更改以解决此警告？警告如下:

在iOS 9中不推荐使用sendAsynchronousRequest,使用dataTaskWithRequest:completionHandler

这是我的代码:

func collectionView(collectionView: UICollectionView, cellForItemAtIndexPath indexPath: NSIndexPath) -> UICollectionViewCell {

    // try to reuse cell
    let cell = collectionView.dequeueReusableCellWithReuseIdentifier(reuseIdentifier, forIndexPath: indexPath) as! MarcaCollectionViewCell

    // get the deal image
    let currentImage = marcas[indexPath.row].imagen
    let unwrappedImage = currentImage
    var image = self.imageCache[unwrappedImage]
    let imageUrl = NSURL(string: marcas[indexPath.row].imagen)

    // reset reused cell image to placeholder
    cell.marcaImageView.image = UIImage(named: "")

    // async image
    if image == nil {

        let request: NSURLRequest = NSURLRequest(URL: imageUrl!)
        NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue(), completionHandler: {(response: NSURLResponse?,data: NSData?,error: NSError?) -> Void in
            if error == nil {

                image = UIImage(data: data!)

                self.imageCache[unwrappedImage] = image
                dispatch_async(dispatch_get_main_queue(), {
                    cell.marcaImageView.image = image

                })
            }
            else {

            }
        })
    }

    else {
        cell.marcaImageView.image = image
    }

    return cell

}

Answer 1

警告警告,NSURLConnection已经死亡.NSURLSession万岁.

let session = NSURLSession.sharedSession()
let urlString = "https://api.yoursecureapiservergoeshere.com/1/whatever"
let url = NSURL(string: urlString)
let request = NSURLRequest(URL: url!)
let dataTask = session.dataTaskWithRequest(request) { (data:NSData?, response:NSURLResponse?, error:NSError?) -> Void in
  print("done, error: \(error)")
}
dataTask.resume()