Array.contains返回false

Gio*_*zzi 3 contains ios swift swift2

我有一组[User]叫做conversationUsers 的用户

用户定义为

public class User: NSManagedObject { ... }
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并且currUser是一个User对象

如果我试试

currUser == conversationUsers[0]
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结果是真的

conversationUsers.contains(currUser)
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结果错了

相反,我使用

conversationUsers.contains({$0 == currUser})
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它返回true

仅供参考我还定义了这个:

public func ==(lhs: User, rhs: User) -> Bool {

    let logicalExpression = lhs.email.lowercaseString == rhs.email.lowercaseString

    return logicalExpression

}
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为什么包含返回false?这是他的默认谓词?

谢谢您的帮助

mix*_*xel 6

UPDATE

简而言之,您应该覆盖NSObject.isEqual()方法:

public class User: NSManagedObject { 
    ... 
    override func isEqual(object: AnyObject?) -> Bool {
        if let rhs = object as? User {
            return self == rhs
        }
        return false
    }
}
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我做了一点研究.似乎如果类A继承自NSObject那时的集合方法,比如contains使用NSObject.isEqual()方法来确定两个对象的相等性.类B不是从中继承的,NSObject因此contains方法按预期工作.

import Foundation

class A: NSObject {
    var value: Int

    init(_ value: Int) {
        self.value = value
    }
}

func ==(lhs: A, rhs: A) -> Bool {
    return lhs.value == rhs.value
}

var a = A(1)
var array: [A] = [a, A(2)]
array.contains(a) // true
array.contains(A(1)) // false
array.contains { $0 == A(1) } // true
array[0] == A(1) // true


class B: Equatable {
    var value: Int

    init(_ value: Int) {
        self.value = value
    }
}

func ==(lhs: B, rhs: B) -> Bool {
    return lhs.value == rhs.value
}

var b = B(1)
var array2: [B] = [b, B(2)]
array2.contains(b) // true
array2.contains(B(1)) // true
array2.contains { $0 == B(1) } // true
array2[0] == B(1) // true
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所以你需要覆盖NSObject.isEqual()方法:

class A: NSObject {
    var value: Int

    init(_ value: Int) {
        self.value = value
    }

    override func isEqual(object: AnyObject?) -> Bool {
        if let rhs = object as? A {
            return self == rhs
        }
        return false
    }
}
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老答复

User类也应符合Equatable协议:

extension User: Equatable {}
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或者您可以将其直接添加到类定义中:

public class User: NSManagedObject, Equatable {}
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