PHP - 字符串替换SyntaxError:非法字符

Question

$ status的输出

Array
(
    [1] => 1
    [2] => 0
    [3] => 0
    [4] => 4
    [5] => 4
)

$color_code_string = implode(",",$status);

输出继电器

1,0,0,4,4

$color_code_string = str_replace("0","'#F00'",$color_code_string); 
$color_code_string = str_replace("1","'#00bcd4'",$color_code_string);
$color_code_string = str_replace("2","'#4caf50'",$color_code_string);
$color_code_string = str_replace("3","'#bdbdbd'",$color_code_string);
$color_code_string = str_replace("4","'#ff9900'",$color_code_string);

例外

SyntaxError: illegal character
colors: ['#00bcd'#ff9900'','#F00','#F00','#ff9900','#ff9900']

//prints '#00bcd'#ff9900'','#F00','#F00','#ff9900','#ff9900'

如何实现预期输出如下

'#00bcd','#ff9900','#F00','#F00','#ff9900','#ff9900'

Answer 1

之所以发生这种情况,是因为您还要替换之前替换的颜色代码中的数字.解决方案:在插入颜色数组之前遍历数组以进行替换:

// Translation table, saves you separate lines of stringreplace calls.
$colorCodes = array(
  0 => "#F00",
  1 => "#00bcd4",
  2 => "#4caf50",
  3 => "#bdbdbd",
  4 => "#ff9900",
);

// Build an array of colors based on the array of status codes and the translation table.
// I'm adding the quotes here too, but that's up to you.
$statusColors = array();
foreach($status as $colorCode) {
  $statusColors[] = "'{$colorCodes[$colorCode]}'";
} 

// Last step: implode the array of colors.
$colors = implode(','$statusColors);