Python - 如何获取所有实例而不仅仅是页面上的第一个实例

Question

使用findAll给出错误"TypeError:list indices必须是整数,而不是str",其中使用.find没有.使用findall给出错误"TypeError:'NoneType'对象不可调用".

定位页面上具有"框架"类的所有链接的正确方法是什么,而不仅仅是第一个实例？

import requests
from bs4 import BeautifulSoup

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/page/2/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/page/3/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/page/4/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/page/5/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/page/6/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/page/7/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/page/8/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

url = ("http://www.gym-directory.com/listing-category/gyms-fitness-centres/page/9/")
r = requests.get(url)
soup = BeautifulSoup(r.text, 'html.parser')
print soup.findAll("a",{"class":"frame"})["href"]

Answer 1

问题是soup.findAll()返回a list,并且您尝试访问该列表["href"]

你需要做的是:

for elem in soup.findAll("a", {"class": "frame"}):
    print elem["href"]