And*_*Liu 5 java polymorphism json dictionary jackson
我搜索了很多,只找到有关地图内容的多态反序列化的问题.是否有可能对地图本身进行多态反序列化?
例如,我有一个Book类包含一个Map作为成员变量.
public class Book {
@JsonProperty
private Map<String, Object> reviews;
@JsonCreator
public Book(Map<String, Object> map) {
this.reviews = map;
}
}
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另一个类有一个Book类列表.
public class Shelf {
@JsonProperty
private List<Book> books = new LinkedList<>();
public void setBooks(List<Book> books) {
this.books = books;
}
public List<Book> getBooks() {
return this.books;
}
}
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还有一个测试课.一本书的评论地图是Hashtable,另一本书的评论地图是HashMap.
public class Test {
private Shelf shelf;
@BeforeClass
public void init() {
Map<String, Object> review1 = new Hashtable<>(); // Hashtable here
review1.put("test1", "review1");
Map<String, Object> review2 = new HashMap<>(); // HashMap here
review2.put("test2", "review2");
List<Book> books = new LinkedList<>();
books.add(new Book(review1));
books.add(new Book(review2));
shelf = new Shelf();
shelf.setBooks(books);
}
@Test
public void test() throws IOException{
ObjectMapper mapper = new ObjectMapper();
mapper.configure(SerializationFeature.INDENT_OUTPUT, true);
// mapper.enableDefaultTyping(ObjectMapper.DefaultTyping.NON_FINAL);
String json = mapper.writeValueAsString(shelf);
System.out.println(json);
Shelf sh = mapper.readValue(json, Shelf.class);
for (Book b : sh.getBooks()) {
System.out.println(b.getReviews().getClass());
}
}
}
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测试输出
{
"name" : "TestShelf",
"books" : [ {
"reviews" : {
"test1" : "review1"
}
}, {
"reviews" : {
"test2" : "review2"
}
} ]
}
class java.util.LinkedHashMap
class java.util.LinkedHashMap
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序列化工作正常.但是在反序列化之后,review1和review2都是LinkedHashMap.我希望review1和review2成为他们的实际类型,它们是Hashtable to review1和HashMap to review2.有没有办法实现这个目标?
我不想使用,mapper.enableDefaultTyping(ObjectMapper.DefaultTyping.NON_FINAL);因为它将在json消息中添加所有json属性的类型信息.如果有更好的方法,我也不想使用自定义的反序列化器.提前致谢.
我在 Jackson 用户论坛上发布了这个问题,他们建议自定义TypeResolverBuilder并在 ObjectMapper 实例中设置它。
ObjectMapper.setDefaultTyping(...)
我的定制TypeResolverBuilder如下,它解决了我的问题。
public class MapTypeIdResolverBuilder extends StdTypeResolverBuilder {
public MapTypeIdResolverBuilder() {
}
@Override
public TypeDeserializer buildTypeDeserializer(DeserializationConfig config,
JavaType baseType, Collection<NamedType> subtypes) {
return useForType(baseType) ? super.buildTypeDeserializer(config, baseType, subtypes) : null;
}
@Override
public TypeSerializer buildTypeSerializer(SerializationConfig config,
JavaType baseType, Collection<namedtype> subtypes) {
return useForType(baseType) ? super.buildTypeSerializer(config, baseType, subtypes) : null;
}
/**
* Method called to check if the default type handler should be
* used for given type.
* Note: "natural types" (String, Boolean, Integer, Double) will never
* use typing; that is both due to them being concrete and final,
* and since actual serializers and deserializers will also ignore any
* attempts to enforce typing.
*/
public boolean useForType(JavaType t) {
return t.isMapLikeType() || t.isJavaLangObject();
}
}
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该解决方案需要服务器端和客户端都使用定制的TypeResolverBuilder. 我知道这并不理想,但这是我迄今为止找到的最佳解决方案。解决方案的详细信息可以在我的博客上的这篇文章中找到。
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