我目前正在学习一个教程,以帮助我学习JavaFX的工作原理,在教程中他们正在构建一个小应用来管理人们的信息.本教程还使用XML进行加载/保存,但我不想使用XML并且想要使用JSON.我有一个Person使用的模型StringProperty,IntegerProperty和ObjectProperty.我的问题是,我不确定加载和保存这个的最佳方法是什么,如果没有它保存不必要的字段,也加载没有Gson抛出错误.
import java.time.LocalDate;
import javafx.beans.property.IntegerProperty;
import javafx.beans.property.ObjectProperty;
import javafx.beans.property.SimpleIntegerProperty;
import javafx.beans.property.SimpleObjectProperty;
import javafx.beans.property.SimpleStringProperty;
import javafx.beans.property.StringProperty;
/**
* Model class for a Person.
*
* @author Marco Jakob
*/
public class Person {
private final StringProperty firstName;
private final StringProperty lastName;
private final StringProperty street;
private final IntegerProperty postalCode;
private final StringProperty city;
private final ObjectProperty<LocalDate> birthday;
/**
* Default constructor.
*/
public Person() {
this(null, null);
}
/**
* Constructor with some initial data.
*
* @param firstName
* @param lastName
*/
public Person(String firstName, String lastName) {
this.firstName = new SimpleStringProperty(firstName);
this.lastName = new SimpleStringProperty(lastName);
// Some initial dummy data, just for convenient testing.
this.street = new SimpleStringProperty("some street");
this.postalCode = new SimpleIntegerProperty(1234);
this.city = new SimpleStringProperty("some city");
this.birthday = new SimpleObjectProperty<LocalDate>(LocalDate.of(1999, 2, 21));
}
public String getFirstName() {
return firstName.get();
}
public void setFirstName(String firstName) {
this.firstName.set(firstName);
}
public StringProperty firstNameProperty() {
return firstName;
}
public String getLastName() {
return lastName.get();
}
public void setLastName(String lastName) {
this.lastName.set(lastName);
}
public StringProperty lastNameProperty() {
return lastName;
}
public String getStreet() {
return street.get();
}
public void setStreet(String street) {
this.street.set(street);
}
public StringProperty streetProperty() {
return street;
}
public int getPostalCode() {
return postalCode.get();
}
public void setPostalCode(int postalCode) {
this.postalCode.set(postalCode);
}
public IntegerProperty postalCodeProperty() {
return postalCode;
}
public String getCity() {
return city.get();
}
public void setCity(String city) {
this.city.set(city);
}
public StringProperty cityProperty() {
return city;
}
public LocalDate getBirthday() {
return birthday.get();
}
public void setBirthday(LocalDate birthday) {
this.birthday.set(birthday);
}
public ObjectProperty<LocalDate> birthdayProperty() {
return birthday;
}
}
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personData是ObservableList的Person小号try (Writer writer = new FileWriter(file)) {
new GsonBuilder().setPrettyPrinting().disableHtmlEscaping().create().toJson(personData, writer);
}
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节约的这种方式目前生产与节约很多喜欢不必要的字段中name,value等时也可能是"firstName": "Hans"
[{
"firstName": {
"name": "",
"value": "Hans",
"valid": true,
"helper": {
"observable": {}
}
},
"lastName": {
"name": "",
"value": "Muster",
"valid": true,
"helper": {
"observable": {}
}
},
"street": {
"name": "",
"value": "some street",
"valid": true
},
"postalCode": {
"name": "",
"value": 1234,
"valid": true
},
"city": {
"name": "",
"value": "some city",
"valid": true
},
"birthday": {}
}]
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现在,即使尝试使用Gson加载上面的字符串,也会产生错误Failed to invoke public javafx.beans.property.StringProperty() with no args.
Person[] persons;
try (Reader reader = new FileReader(file)) {
persons = gson.fromJson(reader, Person[].class);
}
personData.clear();
personData.addAll(persons);
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我用谷歌搜索看看是否有可能使用Gson的getter和setter但是它似乎不太可能,所以我坚持做什么.
Jof*_*rey 16
我知道我有点迟到了,但这是为了未来的读者.
我有同样的问题.我最终编写了一堆Gson TypeAdapter,每个JavaFX属性类型一个(还有一些用于Color和Font).
我将它们全部收集在一个名为FxGson(<30kB)的轻量级库中.
现在,只需使用FxGson GsonBuilder,JavaFX POJO就会被序列化,就像它们的属性是简单值一样.Person在示例中使用该类:
Person p = new Person("Hans", "Muster");
Gson gson = FxGson.coreBuilder().setPrettyPrinting().disableHtmlEscaping().create();
System.out.println(gson.toJson(p));
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这输出:
{
"firstName": "Hans",
"lastName": "Muster",
"street": "some street",
"postalCode": 1234,
"city": "some city",
"birthday": {
"year": 1999,
"month": 2,
"day": 21
}
}
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