dan*_*gel 5 php mysql arrays laravel eloquent
给定以下表结构,我想返回一个 Eloquent 集合,或者至少将原始数据库结果转换为关联数组以便于迭代。
建筑物
+----+---------------+
| id | building_name |
+----+---------------+
| 1 | Building 1 |
| 2 | Building 2 |
+----+---------------+
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客房
+----+-----------+-------------+
| id | room_name | building_id |
+----+-----------+-------------+
| 1 | Room 1 | 1 |
| 2 | Room 2 | 1 |
| 3 | Room 3 | 2 |
+----+-----------+-------------+
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维护日志
+----+-------------------+---------+---------------------+
| id | maintenance_value | room_id | created_at |
+----+-------------------+---------+---------------------+
| 1 | Cleaned | 1 | 2015-09-10 00:54:59 |
| 2 | Cleaned | 1 | 2015-09-13 01:55:59 |
| 3 | Cleaned | 2 | 2015-09-09 02:56:59 |
| 4 | Cleaned | 2 | 2015-09-14 03:57:59 |
| 5 | Cleaned | 3 | 2015-09-08 04:58:59 |
| 6 | Cleaned | 3 | 2015-09-15 05:59:59 |
+----+-------------------+---------+---------------------+
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现在使用以下原始数据库查询..
$results = DB::select('
select b.building_name,r.room_name,x.maxdate FROM buildings b
join rooms r on r.building_id = b.id
join (select room_id,max(created_at) as maxdate from maintenancelog group by room_id) x on x.room_id=room.id
having x.maxdate < DATE_SUB(NOW(), INTERVAL 10 DAY)');
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返回
Array
(
[0] => stdClass Object
(
[building_name] => Building 1
[room_name] => Room 1
[maxdate] => 2015-09-13 01:55:59
)
[1] => stdClass Object
(
[building_name] => Building 1
[room_name] => Room 2
[maxdate] => 2015-09-14 03:57:59
)
[2] => stdClass Object
(
[building_name] => Building 2
[room_name] => Room 3
[maxdate] => 2015-09-15 05:59:59
)
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是否有给定数组的 Laravel 辅助函数,我可以指定键和分组顺序?有点像,按 building_name,room_name 分组,以便它返回一个集合或关联数组,其中“建筑物”和“房间”作为键,使迭代更容易?我可以建立一个,但这似乎是一项常见的任务。(我确实搜索过)
我正在使用 Eloquent 并为表创建了模型,但是查询太复杂了,我无法弄清楚如何将其转换为 Eloquent 语句。那么即使有一种方法可以使用现有模型创建集合?
(请注意,我已经弄清楚如何使用关系和查询范围从维护日志 -> 房间 -> 建筑物向后工作。但它将建筑物置于关系的最低级别,我希望它是第一个)
在建筑类中:
public function rooms(){
return $this->hasMany('App\Room');
}
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在房间类别中:
public function maintenanceLog(){
return $this->hasMany('App\MaintenanceLog');
}
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在维护日志类中:
public function scopeLongest($query){ //you can name it as you like ofc.
return $query->orderBy('created_at','desc')->first();
}
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最后你可以使用:
foreach(Building::all() as $building){
foreach($building->rooms() as $room){
echo 'building: ' . $building->building_name . ' room: ' . $room->room_name . ' maxdate: ' . $room->maintenanceLog()->longest()->created_at;
}
}
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