使用c#一般地拼合Json

Question

我想一般扁平一些json所以我可以转换为数据表并使用c#绑定到数据网格

什么是最好的办法,记住我不知道我要下多少级别？

例如

{
  "appointmentid": 4,
  "policyid": 1,
  "guid": "00000000-0000-0000-0000-000000000000",
  "number": "1234567890",
  "ampm": "false",
  "date": "2015-09-08T00:00:00",
  "vehicle": {
    "id": 1,
    "guid": "00000000-0000-0000-0000-000000000000",
    "make": null,
    "model": null
  },
  "installer": {
    "installerid": "1",
    "name": "Installer 1",
    "contact": "qwerty",
    "qascore": "0",
    "address1": "qwerty",
    "address2": "qwerty",
    "address3": null,
    "address4": null,
    "city": "qwertyu",
    "county": "qwertyu",
    "postcode": "asdfghj",
    "country": "GB",
    "email": "asdfghj",
    "web": "asdfghjk",
    "archived": false
  },
  "installations": [
    {
      "installationid": 6,
      "installationstatus": {
        "installationstatusid": 4,
        "installationstatus": "FAIL"
      },
      "isactive": true
    },
    {
      "installationid": 7,
      "installationstatus": {
        "installationstatusid": 1,
        "installationstatus": "NEW"
      },
      "isactive": false
    }
  ],
  "archived": false
}

我想扩展这个(我想我可以迭代我转换它的数据表)而不是instal.1.installationid,我会得到installationid1.

因为我要在网格中显示结果数据表,我想保持列名称友好.

Answer 1

您可以使用Json.Net的LINQ-to-JSON API将数据解析为JToken结构.从那里,您可以使用递归辅助方法来遍历结构并将其展平到Dictionary<string, object>键是从原始JSON到每个值的"路径"的位置.我会写这样的东西:

public class JsonHelper
{
    public static Dictionary<string, object> DeserializeAndFlatten(string json)
    {
        Dictionary<string, object> dict = new Dictionary<string, object>();
        JToken token = JToken.Parse(json);
        FillDictionaryFromJToken(dict, token, "");
        return dict;
    }

    private static void FillDictionaryFromJToken(Dictionary<string, object> dict, JToken token, string prefix)
    {
        switch (token.Type)
        {
            case JTokenType.Object:
                foreach (JProperty prop in token.Children<JProperty>())
                {
                    FillDictionaryFromJToken(dict, prop.Value, Join(prefix, prop.Name));
                }
                break;

            case JTokenType.Array:
                int index = 0;
                foreach (JToken value in token.Children())
                {
                    FillDictionaryFromJToken(dict, value, Join(prefix, index.ToString()));
                    index++;
                }
                break;

            default:
                dict.Add(prefix, ((JValue)token).Value);
                break;
        }
    }

    private static string Join(string prefix, string name)
    {
        return (string.IsNullOrEmpty(prefix) ? name : prefix + "." + name);
    }
}

将此DeserializeAndFlatten方法与您的JSON一起使用,最终会得到如下键值对:

appointmentid: 4
policyid: 1
guid: 00000000-0000-0000-0000-000000000000
number: 1234567890
ampm: false
date: 9/8/2015 12:00:00 AM
vehicle.id: 1
vehicle.guid: 00000000-0000-0000-0000-000000000000
vehicle.make:
vehicle.model:
installer.installerid: 1
installer.name: Installer 1
installer.contact: qwerty
installer.qascore: 0
installer.address1: qwerty
installer.address2: qwerty
installer.address3:
installer.address4:
installer.city: qwertyu
installer.county: qwertyu
installer.postcode: asdfghj
installer.country: GB
installer.email: asdfghj
installer.web: asdfghjk
installer.archived: False
installations.0.installationid: 6
installations.0.installationstatus.installationstatusid: 4
installations.0.installationstatus.installationstatus: FAIL
installations.0.isactive: True
installations.1.installationid: 7
installations.1.installationstatus.installationstatusid: 1
installations.1.installationstatus.installationstatus: NEW
installations.1.isactive: False
archived: False

如果你想让键更加人性化,你可以使用一些字符串操作来削减它们.也许是这样的:

var dict = JsonHelper.DeserializeAndFlatten(json);
foreach (var kvp in dict)
{
    int i = kvp.Key.LastIndexOf(".");
    string key = (i > -1 ? kvp.Key.Substring(i + 1) : kvp.Key);
    Match m = Regex.Match(kvp.Key, @"\.([0-9]+)\.");
    if (m.Success) key += m.Groups[1].Value;
    Console.WriteLine(key + ": " + kvp.Value);
}

这会给你这个输出:

appointmentid: 4
policyid: 1
guid: 00000000-0000-0000-0000-000000000000
number: 1234567890
ampm: false
date: 9/8/2015 12:00:00 AM
id: 1
guid: 00000000-0000-0000-0000-000000000000
make:
model:
installerid: 1
name: Installer 1
contact: qwerty
qascore: 0
address1: qwerty
address2: qwerty
address3:
address4:
city: qwertyu
county: qwertyu
postcode: asdfghj
country: GB
email: asdfghj
web: asdfghjk
archived: False
installationid0: 6
installationstatusid0: 4
installationstatus0: FAIL
isactive0: True
installationid1: 7
installationstatusid1: 1
installationstatus1: NEW
isactive1: False
archived: False

但请注意,通过这种安排,您丢失了一些上下文:例如,您可以看到现在有两个相同的archived键,而在原始的JSON中它们是不同的,因为它们出现在层次结构的不同部分(installer.archived相对archived).你需要弄清楚如何自己处理这个问题.

小提琴:https://dotnetfiddle.net/gzhWHk

Answer 2

使用库Json.Net您可以使用 JSONPath$..*获取 JSON 结构的所有成员，并过滤掉没有子级的成员以跳过容器属性。

例如

var schemaObject = JObject.Parse(schema);
var values = schemaObject
    .SelectTokens("$..*")
    .Where(t => !t.HasValues)
    .ToDictionary(t => t.Path, t => t.ToString());

Answer 3

另一种变体使用 Newtonsoft 的 Json.NET LINQ to JSON作为根对象（也可以这样做JArray）：

var flattened = JObject.Parse(json)
    .Descendants()
    .OfType<JValue>()
    .ToDictionary(jv => jv.Path, jv => jv.ToString())